![]() |
|
|
#705 |
|
Aug 2005
Seattle, WA
2·883 Posts |
|
|
|
|
|
|
#706 |
|
Nov 2003
164448 Posts |
I mean no insult to Tomer in what I am going to say,
but he really thinks that he knows a lot of things that he really doesn't know. It is surely not his fault; I'm sure that the training he received has been inadequate to really do proofs. He seems to have very poor training in the use of definitions, use of variables, substitution of variables, and his derivations just lack rigor. He would benefit greatly from a disciplined proof-based course in Eulclidean Geometry. |
|
|
|
|
|
#707 | |
|
Jan 2010
37910 Posts |
Quote:
doesn't know." False. I didn't say I know something about the binom (I asked about it in one of the posts, becuase I know it's idea and theme, but I lack skills on the area). And now, after reading Wolfram's page on the binomial coefficients, I may say it is n_C_k=n!/(k!(n-k)!). Last fiddled with by blob100 on 2010-06-24 at 19:24 |
|
|
|
|
|
|
#708 |
|
Jun 2003
The Texas Hill Country
32·112 Posts |
|
|
|
|
|
|
#709 |
|
Aug 2005
Seattle, WA
2×883 Posts |
Okay, you may say it, but do you understand it? In what circumstances might it be useful? Can you see how it applies to the polynomial coefficient problem? This is what I meant when I said that you needed to "think about this information".
|
|
|
|
|
|
#710 |
|
Jan 2010
17B16 Posts |
|
|
|
|
|
|
#711 |
|
Jun 2003
The Texas Hill Country
44116 Posts |
|
|
|
|
|
|
#712 |
|
Jan 2010
5738 Posts |
|
|
|
|
|
|
#713 | |
|
Aug 2005
Seattle, WA
2·883 Posts |
Quote:
He is untrained and lacks rigor. Well that's not a fatal flaw. I think he just hasn't been exposed to that way of thinking much. All of your complaints about his definitions, variables, derivations, etc. are really just symptoms of this lack of exposure. Learning to do proofs is a bit like learning a foreign language; to some degree there's just a style to which one must become accustomed, and being immersed in that is the best way to learn it. You're probably right about a course in geometry, partly because he just needs to spend some time learning to do rigorous proofs, and partly because geometry is a good vehicle for maintaining that sense of fun: who doesn't like drawing pictures? Of course there's really no way to give him geometry problems in this forum, but there are other kinds of problems we could give him that are very simple and would help him practice proofs. |
|
|
|
|
|
|
#714 |
|
Jan 2010
379 Posts |
Proof by induction (binomial theorem):
We see define nCk as the number of combinations of k units taken from a set of n units. Proposition: nCk=(n!)/(P!k!) P=n-k. We will do so by induction on n. Step 1: Showing 0Ck agree the terms (for n=0, the proposition is true). 0Ck=1. (0!)/(P!k!)=1/(1*1)=1. Step 2: Assuming that the formula is true for a given n and all 0≤ k≤n. Step 3: Showing that for n+1 the proposition is true if it is for n. We assumed: nCk=(n!)/(P!k!), And we try to prove: n+1Ck=((n+1)!)/(P!k!). We see: k=0, ((n+1)!)/((n+1)!0!)=1. And: k=n+1, ((n+1)!)/(0!(n+1)!)=1 And for 0≤ k≤n, nCk+nCk-1. So, we try porving nCk+nCk-1 is equivallent to (n+1)!/((n+1-k)!k!). n!/(n-k)!k!+n!/(n-k+1)!(k-1)!=n!(n-k+1)/(n-k+1)!k!+n!k/(n-k+1)!k!= n!(n+1)/(n-k+1)!k!. Now, we would easily propose the next equation: n!(n+1)/(n-k+1)!k!=(n+1)!/((n+1-k)!k!), Which is what we tried to prove. Last fiddled with by blob100 on 2010-06-24 at 20:54 |
|
|
|
|
|
#715 | |
|
Jan 2010
5738 Posts |
Quote:
Do you agree with me? |
|
|
|
|
![]() |
| Thread Tools | |
Similar Threads
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Some ideas regarding NFS... | paul0 | Factoring | 3 | 2015-03-14 19:55 |
| Ideas for the future beyond just-keep-encrunching | Dubslow | NFS@Home | 13 | 2015-02-02 22:25 |
| two ideas for NPLB | Mini-Geek | No Prime Left Behind | 16 | 2008-03-01 23:32 |
| GROUP IDEAS | TTn | 15k Search | 15 | 2003-09-23 16:28 |
| Domain name ideas... | Xyzzy | Lounge | 17 | 2003-03-24 16:20 |