Bases 251-500 reservations/statuses/primes

[paleseptember]

Thanks Mathew!

(In my defence, it's been a long day.)

[gd_barnes]

S320 is complete to n=25K; no primes for n=5K-25K; 3 k's remaining; largest prime 49*320^2580+1; base released.

Reserving S334 to n=25K.

[gd_barnes]

Reserving S410 to n=25K.

[paleseptember]

I made an error in my post above. I was testing Riesel 425, not Sierpinski 425.

Riesel 425 is complete to n=25K. Only k=8 remains (conj. k=70). Results emailed to Gary.

[gd_barnes]

Originally Posted by paleseptember

I made an error in my post above. I was testing Riesel 425, not Sierpinski 425.

Riesel 425 is complete to n=25K. Only k=8 remains (conj. k=70). Results emailed to Gary.

Unfortunately, you were actually testing Sierp base 425. Here is what happened:

1. You reserved and tested Sierp 425 for n<=2500. As you stated, only k=8 remained.
2. You tested Riesel 425 k=8 for n>2500.

There is a silver lining in this. I see what happened. In looking at the results file, I'm fairly certain that your sieve file is correct except for one small thing: You changed the header to -1 instead of +1. In other words, you tested the n-values that were intended for 8*425^n+1 for 8*425^n-1 instead after you had correctly sieved it. I am fairly certain of this because you are testing n-values such as n=11 and n=53. Had you sieved 8*425^n-1, those n-values would have been quickly sieved out with a factor of 3. So your sieve file should be correct for 8*425^n+1 if you make that small change. Then you'll be able to quickly rerun it and get good tests.

On the Riesel side, k=8 is eliminated quickly because 8*425^2-1 (and 8*425^10-1) are prime.

Both sides have the same conjecture of k=70; a fairly common occurrence, which can make it easy to confuse the 2 sides.

I just now did a quick run for R425 to n=2500. k=46, 50, and 64 remain.

Usually I'd like bases to be at n>=10K before showing on the pages but based on the situation, I'll go ahead and show both sides of base 425 at n=2500 with their applicable k's remaining. (Note Ian: S425 won't get shown in the 1k thread until it's searched to n=25K.)

You can choose to do one of 4 things:

1. Test S425 k=8 for n=2500-25K.
2. Test R425 k=46, 50, and 64 for n=2500-25K.
3. Do them both.
4. Do nothing at all.

Let me know what you decide. I'll show all of the applicable info. on the pages for both sides. Whatever you choose to do, I'll reserve or keep it reserved for you. Whatever remains after you are done, with the CK=70 on both sides, they will likely get tested fairly soon by someone.


Gary

[paleseptember]

I think that it had been a long day, and my general daftness mean that it's just a big headdesk of fail on my account.

Gaaahhh!

Okay. I shall tackle option 3. That is, test S425 and R425 from 2500 to 25K. I shall attempt to not mistake + for - this time.

[rogue]

Rerserving these single k conjectures:
64*259^n+1
55*266^n+1
4*335^n+1
10*341^n+1
20*401^n+1
14*334^n-1
22*347^n-1

[rogue]

55*266^32246+1 is prime!

Conjecture proven.

[gd_barnes]

S334 is complete to n=25K; no primes for n=5K-25K; 3 k's remaining; largest prime 49*334^951+1; base released.

[paleseptember]

For Sierpinski 425, k=8 remains, tested to n=25,000.

For Riesel 425, k=64 remains, tested to n=25,000. Along the way primes for k=46 and k=50 were found. Results to Gary, etc...

Bases released

[paleseptember]

(Yes, I checked that it was Sierpinksi :P)

Sierpinksi 426, conjectured k=62.
Tested to n=5K, only k=8 remains.
Will continue to n=25K.