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View Poll Results: Which driver is the worst for termination?
2*3 1 6.67%
2^2*7 5 33.33%
2^3*3*5 6 40.00%
2^4*31 1 6.67%
2^5*3*7 0 0%
2^6*127 1 6.67%
2^9*3*11*31 0 0%
Other 1 6.67%
Voters: 15. You may not vote on this poll

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Old 2009-10-22, 14:55   #1
Greebley
 
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Default Poll: Which is the worst driver

I was curious what people thought was the worst driver. By this I mean the driver that you least like to see. Basically it is the one that the hardest one to escape before the sequence reaches numbers too high to continue.

Commonness can also enter into your choice; some drivers are hard to escape, but fairly rare so effect only a very few sequences.
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Old 2009-10-22, 16:19   #2
Mini-Geek
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I think 2^43112608*(2^43112609-1) would be the hardest known driver to escape from, but thankfully it's exceedingly rare for our purposes.
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Old 2009-10-22, 16:35   #3
Greebley
 
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Ya, that's why I stated it as "worst" rather than "hardest to escape".

Note though that once you get a square on the big term, the chances of having a power of two high enough is very small, so multiples of large perfect numbers will tend to escape the first time they get a square unless the value is truly huge (big enough to have billions of factors on average)
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Old 2009-10-22, 17:40   #4
henryzz
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2^2*7 is the one that annoys me most
i would guess that 2^6 * 127 is the hardest listed driver to escape
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Old 2009-10-22, 17:49   #5
BigBrother
 
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Quote:
Originally Posted by henryzz View Post
2^2*7 is the one that annoys me most
i would guess that 2^6 * 127 is the hardest listed driver to escape
2^2*7 is my nemesis too. And I always hate it when a 5 shows up!
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Old 2009-10-22, 17:52   #6
henryzz
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Quote:
Originally Posted by BigBrother View Post
2^2*7 is my nemesis too. And I always hate it when a 5 shows up!
if it comes to hating a particular factor i would say definitely 3
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Old 2009-10-22, 18:06   #7
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I hate 2*3 driver. Never met 2^9*3*11*31
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Old 2009-10-22, 18:25   #8
henryzz
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Quote:
Originally Posted by unconnected View Post
I hate 2*3 driver. Never met 2^9*3*11*31
2*3 is possibly the easiest perfect number driver to lose i think
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Old 2009-10-24, 07:45   #9
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I voted 2^4 * 31 because I've never encountered 2^6 * 127 myself, but I have encountered 2^4 * 31 a lot. (And I've only ever escaped it once.)
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