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Old 2009-12-06, 13:30   #298
Mini-Geek
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Quote:
Originally Posted by EdH View Post
I ran across a couple of new prime factors for iteration 574 of number 730536 while playing with a C++ program I'm writing and playing with. Those factors are:

12541 and 71670491

I really have no easy way to verify my findings, so I don't know if they are valid.
They are. http://factordb.com/search.php?se=1&...&fr=574&to=574 Syd's DB is already well past iteration 574 for aliquot sequence 730536. 10metreh: But it wasn't when EdH posted.
Quote:
Originally Posted by EdH View Post
Do new factors get tested when entered?
Yes. The DB always checks that new factors do indeed divide the number, and will simply ignore any factors that don't work. It will also calculate the remaining portion and whether that is composite or prime.

Last fiddled with by 10metreh on 2009-12-06 at 13:39
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Old 2009-12-06, 14:12   #299
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Done with 730224, 100 digits, 2*3
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Old 2009-12-06, 15:17   #300
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done with 730428: size 100, 2^4*3*31
reserving 735294, 735960, 736002, 736680, 737490, 737640, 738528, 738678, 739398, 739788.
735966 is done for the subproject
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Old 2009-12-06, 16:09   #301
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unreserving 730260 at size 100, 2²*7
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Old 2009-12-07, 19:10   #302
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reserving 734052
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Old 2009-12-08, 11:04   #303
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Done with
730536, 730680, 731208, 731232, 731424, 731500, 731562,
735096, 736794, 736820, 736938, 737550, 738072, 738288,
and 650496 (because 736938 merged in it)

731208 extended from i362 to i3,831 (after reaching 100-digits already at i419)... too bad.

I'll keep 737550 reserved for the other thread.

Last fiddled with by Batalov on 2009-12-08 at 11:12 Reason: keeping 737550
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Old 2009-12-08, 12:23   #304
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Reserving
739032, 739152, 739254, 739302, 739464, 739686, 739920
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Old 2009-12-08, 15:11   #305
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Done with 733800, 102 digits, 2^2*3*7
Keeping 733866 reserved at 114 digits (so done for project). It has the guide 2^11*3*5*7 which is 5 factors of 2 short (the full guide 2^11*3*5*7*39 is only 2 short so just misses being a driver).
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Old 2009-12-08, 18:37   #306
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unreserving 734052; i=638, sz. 101, 2²*3*7
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Old 2009-12-08, 21:41   #307
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Quote:
Originally Posted by Greebley View Post
Done with 733800, 102 digits, 2^2*3*7
Keeping 733866 reserved at 114 digits (so done for project). It has the guide 2^11*3*5*7 which is 5 factors of 2 short (the full guide 2^11*3*5*7*39 is only 2 short so just misses being a driver).
Err. Ignore the full guide statement - it is wrong.
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Old 2009-12-09, 03:15   #308
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Taking 736944, 737034, 737160, 737240, 737664

Last fiddled with by Batalov on 2009-12-09 at 03:24
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