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#1 |
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"Sastry Karra"
Jul 2009
Bridgewater, NJ (USA)
33 Posts |
For the past three months, I am enthusiastically analyzing the known Mersenne’s Prime numbers and trying my best to look for some sort of commonality.
During this process, I found out a peculiar characteristic of prime numbers. I am not sure if this is already proved by other mathematicians or not, but I would like to share with all of you. I ran my software program to test my conjucture. Due to my laptop technical restrictions, I could run from integer 1 thru integer 16. For some unknown reasons, when the integer value is 17, my Laptop is getting “Hung-Up”. So, I started testing from integer 18 onwards and after letting my Laptop run for more than 9 hrs, it is still unable to tell me if 19^19 minus 2 is a Prime or not. If this behaviour is not noticed earlier, then I will let my Laptop to run 24X7 for a week and see how far can I verify. ************************************************************************************************************************************* Conjucture: If p & q are positive primes, n is a positive integer and q = (p^p – 2^n), then the number of q’s are limited. ( I found only 8 Primes when ran from 2 thru 16). Example: 2^2 – 2^1 = 2 ; 2^2 – 2^2 = 0 ; - IGNORED SINCE q = ZERO; 3^3 – 2^1 = 25 – Not a Prime; 3^3 – 2^2 = 23 ; 3^3 – 2^3 = 19 ; 3^3 – 2^4 = 11 ; Here is the Screen Printout of all primes between 3 and 16 tested – found only there are 10 primes with this condition being satisfied. ----------------------------------------------------------------------------------------------------------------------------------------------- At Tue Jun 23 20:02:05 EDT 2009 Checking if 2 to power of 2 minus 2 2 is a PRIME.. --> 2 to power of 2 minus 2 = 2 is a PRIME.. FIRST ONE At Tue Jun 23 20:02:05 EDT 2009 Checking if 3 to power of 3 minus 2 = 25 is a PRIME.. At Tue Jun 23 20:02:05 EDT 2009 Checking if 3 to power of 3 minus 4 = 23 is a PRIME.. --> 3 to power of 3 minus 4 = 23 is a PRIME.. SECOND ONE At Tue Jun 23 20:02:05 EDT 2009 Checking if 3 to power of 3 minus 8 = 19 is a PRIME.. --> 3 to power of 3 minus 8 = 19 is a PRIME.. THIRD ONE At Tue Jun 23 20:02:05 EDT 2009 Checking if 3 to power of 3 minus 16 = 11 is a PRIME.. --> 3 to power of 3 minus 16 = 11 is a PRIME.. FOURTH ONE At Tue Jun 23 20:02:05 EDT 2009 Checking if 5 to power of 5 minus 2 = 3123 is a PRIME.. At Tue Jun 23 20:02:05 EDT 2009 Checking if 5 to power of 5 minus 4 = 3121 is a PRIME.. --> 5 to power of 5 minus 4 = 3121 is a PRIME.. FIFTH ONE At Tue Jun 23 20:02:05 EDT 2009 Checking if 5 to power of 5 minus 8 = 3117 is a PRIME.. At Tue Jun 23 20:02:05 EDT 2009 Checking if 5 to power of 5 minus 16 = 3109 is a PRIME.. --> 5 to power of 5 minus 16 = 3109 is a PRIME.. SIXTH ONE At Tue Jun 23 20:02:05 EDT 2009 Checking if 5 to power of 5 minus 32 = 3093 is a PRIME.. At Tue Jun 23 20:02:05 EDT 2009 Checking if 5 to power of 5 minus 64 = 3061 is a PRIME.. --> 5 to power of 5 minus 64 = 3061 is a PRIME.. SEVENTH ONE At Tue Jun 23 20:02:05 EDT 2009 Checking if 5 to power of 5 minus 128 = 2997 is a PRIME.. At Tue Jun 23 20:02:05 EDT 2009 Checking if 5 to power of 5 minus 256 = 2869 is a PRIME.. At Tue Jun 23 20:02:05 EDT 2009 Checking if 7 to power of 7 minus 2 = 823541 is a PRIME.. --> 7 to power of 7 minus 2 = 823541 is a PRIME.. EIGTH ONE At Tue Jun 23 20:02:08 EDT 2009 Checking if 7 to power of 7 minus 4 = 823539 is a PRIME.. At Tue Jun 23 20:02:08 EDT 2009 Checking if 7 to power of 7 minus 8 = 823535 is a PRIME.. At Tue Jun 23 20:02:08 EDT 2009 Checking if 7 to power of 7 minus 16 = 823527 is a PRIME.. At Tue Jun 23 20:02:08 EDT 2009 Checking if 7 to power of 7 minus 32 = 823511 is a PRIME.. At Tue Jun 23 20:02:08 EDT 2009 Checking if 7 to power of 7 minus 64 = 823479 is a PRIME.. At Tue Jun 23 20:02:08 EDT 2009 Checking if 7 to power of 7 minus 128 = 823415 is a PRIME.. At Tue Jun 23 20:02:08 EDT 2009 Checking if 7 to power of 7 minus 256 = 823287 is a PRIME.. At Tue Jun 23 20:02:08 EDT 2009 Checking if 11 to power of 11 minus 2 = 285311670609 is a PRIME.. At Tue Jun 23 20:02:08 EDT 2009 Checking if 11 to power of 11 minus 4 = 285311670607 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 11 to power of 11 minus 8 = 285311670603 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 11 to power of 11 minus 16 = 285311670595 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 11 to power of 11 minus 32 = 285311670579 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 11 to power of 11 minus 64 = 285311670547 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 11 to power of 11 minus 128 = 285311670483 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 11 to power of 11 minus 256 = 285311670355 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 13 to power of 13 minus 2 = 302875106592251 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 13 to power of 13 minus 4 = 302875106592249 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 13 to power of 13 minus 8 = 302875106592245 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 13 to power of 13 minus 16 = 302875106592237 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 13 to power of 13 minus 32 = 302875106592221 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 13 to power of 13 minus 64 = 302875106592189 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 13 to power of 13 minus 128 = 302875106592125 is a PRIME.. At Tue Jun 23 20:02:10 EDT 2009 Checking if 13 to power of 13 minus 256 = 302875106591997 is a PRIME.. At Thu Jun 25 07:15:28 EDT 2009 Checking if 19 to power of 19 minus 2 = 1978419655660313589123977 is a PRIME.. PROCESS Failed ----------------------------------------------------------------------------------------------------------------------------------------------- -- Thanks, Sastry Karra MS, MBA(MIS) "Good judgement comes from experience and experience comes from Bad judgement" |
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#2 |
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Jun 2003
7·167 Posts |
pari/gp confirms that 19^19-2 is prime. The result is instant. if your laptop is taking 9 hours then there is something wrong with your algorithm.
Why do you not test past 2^n=256? |
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#3 |
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Jun 2003
7·167 Posts |
Incidentally for each
The infinite series for all prime p diverges (rather rapidly, in fact), and so I would expect there to be an infinitude of such primes, contrary to your conjecture. Whether anything can be proven, or whether there are any number-theoretical reasons to doubt my heuristic is beyond by mathematical ability. Last fiddled with by Mr. P-1 on 2009-07-17 at 16:10 |
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#4 |
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Aug 2006
3×1,993 Posts |
Primes:
Code:
2^2 - 2^1 3^3 - 2^2 3^3 - 2^3 3^3 - 2^4 5^5 - 2^2 5^5 - 2^4 5^5 - 2^6 7^7 - 2^1 7^7 - 2^13 17^17 - 2^6 17^17 - 2^20 17^17 - 2^30 17^17 - 2^40 17^17 - 2^64 19^19 - 2^1 19^19 - 2^5 23^23 - 2^66 23^23 - 2^76 31^31 - 2^77 31^31 - 2^97 41^41 - 2^38 41^41 - 2^214 47^47 - 2^60 47^47 - 2^72 53^53 - 2^30 53^53 - 2^50 59^59 - 2^100 61^61 - 2^91 61^61 - 2^327 67^67 - 2^193 73^73 - 2^177 73^73 - 2^189 73^73 - 2^293 83^83 - 2^22 83^83 - 2^116 83^83 - 2^272 83^83 - 2^274 83^83 - 2^290 83^83 - 2^366 83^83 - 2^436 97^97 - 2^407 |
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#5 | |
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Aug 2006
3×1,993 Posts |
Quote:
You can get a better estimate by considering their behavior mod 3, 5, ..., making the expectation if I haven't made a mistake. Anyone want to test this against the numbers I've generated so far? Code:
101^101 - 2^666 103^103 - 2^107 103^103 - 2^159 103^103 - 2^639 103^103 - 2^659 107^107 - 2^6 107^107 - 2^72 107^107 - 2^322 107^107 - 2^352 107^107 - 2^594 109^109 - 2^159 109^109 - 2^679 113^113 - 2^142 113^113 - 2^206 113^113 - 2^488 127^127 - 2^169 127^127 - 2^337 131^131 - 2^70 131^131 - 2^610 131^131 - 2^658 137^137 - 2^134 137^137 - 2^342 137^137 - 2^582 139^139 - 2^227 139^139 - 2^387 139^139 - 2^529 149^149 - 2^304 149^149 - 2^1036 151^151 - 2^181 157^157 - 2^11 157^157 - 2^655 163^163 - 2^263 163^163 - 2^315 163^163 - 2^1011 167^167 - 2^66 167^167 - 2^822 173^173 - 2^8 173^173 - 2^242 173^173 - 2^264 173^173 - 2^452 173^173 - 2^472 173^173 - 2^580 173^173 - 2^710 |
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#6 |
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Jun 2003
7×167 Posts |
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#7 |
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Aug 2006
3×1,993 Posts |
log(p^p) = p log p, so you expect one in p log p to be prime (or two, because of their parity). There are log_2 p^p = p log p / log 2 per p, so 2 * (p log p / log 2) / (p log p) = 2/log 2.
For other 'small enough' primes there are only q-1 ways of being divisible by q, since q doesn't divide p^p and q doesn't divide 2^n. That's what the correction term is trying to do. It's actually not quite right, since I'm not sure how far to take 'small enough'. Maybe if I do an integral rather than a sum...? |
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#8 |
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Jun 2003
22218 Posts |
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#9 |
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"Sastry Karra"
Jul 2009
Bridgewater, NJ (USA)
33 Posts |
Thanks a lot ....
In my conjecture, I mentioned that "the number of q’s are limited. ". Now, I found that there are more than I found..... |
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