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2017-11-22, 18:11
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#607 |
Oct 2006
Berlin, Germany
10011011112 Posts |
1952670 terminated at i1361.
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2017-11-23, 21:13
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#608 |
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Apr 2013
Germany
311 Posts |
The seq(s) 1974448 seem(s) to have merged with 1320480
1320480:1340 = 1974448:12 Which sequence do you delete in this case? Last fiddled with by fivemack on 2017-11-23 at 22:13 |
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2017-11-23, 23:14
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#609 |
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Basketry That Evening!
"Bunslow the Bold"
Jun 2011
40<A<43 -89<O<-88
3·29·83 Posts |
Always remove the larger sequence (1974448)
Last fiddled with by Dubslow on 2017-11-23 at 23:15 |
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2017-11-24, 07:47
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#610 |
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(loop (#_fork))
Feb 2006
Cambridge, England
23·11·73 Posts |
1868148 terminates
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2017-11-24, 12:08
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#611 |
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Apr 2013
Germany
31110 Posts |
The seq(s) 1741632 seem(s) to have merged with 1632
Dubslows code automatically deletes the larger seq when a merge is detected. (1741632:3912 = 1632:37; I have an auto-reporter meaning that I don't necessarily notice merges as they happen) Last fiddled with by fivemack on 2017-11-26 at 08:02 |
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2017-11-25, 10:12
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#612 |
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Romulan Interpreter
Jun 2011
Thailand
25BF16 Posts |
That's the right way.
In my DB however, I keep both the "smallest" and the "longest" sequence that reach some composite. In case someone is looking for long sequences. (my DB entries are [n, s, m, i, z, j, p1, a1, ...], where n is the number, s is its status, m is the smallest sequence reaching n at index i, z is the longest sequence reaching n at index j, and p^a are the factors, except the last (prime or unknown cofactor) - this way mergers are detected automatically, and the same composite is never factored two times) Last fiddled with by LaurV on 2017-11-25 at 10:16 |
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2017-11-30, 18:45
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#613 |
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Oct 2006
Berlin, Germany
7·89 Posts |
1211160 terminated
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2017-12-01, 06:01
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#614 |
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
9,497 Posts |
1938060 terminates @ i4415
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2017-12-10, 18:15
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#616 |
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Oct 2006
Berlin, Germany
62310 Posts |
sequence 1052310 has terminated
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