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#661 |
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Nov 2008
2×33×43 Posts |
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#662 |
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Noodles
"Mr. Tuch"
Dec 2007
Chennai, India
23518 Posts |
Meanwhile, pray up to God that it splits up into two (2 mod 3) factors
![]() I wonder whether you check up the residue class of each factor of each iteration mod 3, 5, 7...? Once it acquires up a factor of 3, in order to lose it up: s(c) = product of (1+p)'s - c. (1+p) is replaced up by (1+p+p2+...) for the prime powers... Since c is divisible by 3, in order to lose the 3, the products of (1+p)'s should be 1 or 2 mod 3. The factor of 3 will not stimulate again a 3 in the next line at all, since (1+3+9+...) is always equal to 1 mod 3. Any of the others should not be divisible by 3 at all. A prime of 2 mod 3, will induce up a 3 in the next line by using (1+p) A prime of 1 mod 3, will not. However, that all of the primes other than 3, cannot be equal to 0 mod 3, anyway. For the prime powers, power of 2 mod 3 will trigger up a 3 if the power is odd. Power of 1 mod 3 will trigger 3, if the power is even. I see that it can lose up the 3 within the next iteration, if for all the primes besides 3, the power of 2 mod 3 primes are all even, and then the power of 1 mod 3 primes are all odd. Or, in fact it is true that it can lose up the 3 within the subsequent iterations by means of using the factor of 9 = 32 All these are natural processes only, by itself. We can't do anything to change sequences, or write up a random number of our own. We just simply compute the results, and then go on processing with the single correct number of the next iteration. Last fiddled with by Raman on 2009-12-24 at 13:52 |
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#663 |
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Oct 2004
Austria
2·17·73 Posts |
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#664 |
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Oct 2004
Austria
2·17·73 Posts |
Code:
Fri Dec 25 20:39:10 2009 Fri Dec 25 20:39:10 2009 Fri Dec 25 20:39:10 2009 Msieve v. 1.43 Fri Dec 25 20:39:10 2009 random seeds: e4aca9c8 a1f403b9 Fri Dec 25 20:39:10 2009 factoring 3942887076714143202481073805784961368619711215403426727623016228578779996971144714931046107405659926915911799176550312767 (121 digits) Fri Dec 25 20:39:12 2009 no P-1/P+1/ECM available, skipping Fri Dec 25 20:39:12 2009 commencing number field sieve (121-digit input) Fri Dec 25 20:39:12 2009 R0: -220525782874300519278221 Fri Dec 25 20:39:12 2009 R1: 10561525245991 Fri Dec 25 20:39:12 2009 A0: 13919992851438837656957797344 Fri Dec 25 20:39:12 2009 A1: -7900337548465327330903242 Fri Dec 25 20:39:12 2009 A2: 14318233152048859923 Fri Dec 25 20:39:12 2009 A3: -542592852133532 Fri Dec 25 20:39:12 2009 A4: -1569762856 Fri Dec 25 20:39:12 2009 A5: 7560 Fri Dec 25 20:39:12 2009 skew 191636.60, size 1.651620e-11, alpha -6.880605, combined = 2.901254e-10 Fri Dec 25 20:39:12 2009 Fri Dec 25 20:39:12 2009 commencing relation filtering Fri Dec 25 20:39:12 2009 estimated available RAM is 1985.8 MB Fri Dec 25 20:39:12 2009 commencing duplicate removal, pass 1 Fri Dec 25 20:39:28 2009 error -15 reading relation 1477379 Fri Dec 25 20:39:48 2009 error -15 reading relation 3405784 Fri Dec 25 20:40:45 2009 found 1083950 hash collisions in 8438938 relations Fri Dec 25 20:41:14 2009 added 58146 free relations Fri Dec 25 20:41:14 2009 commencing duplicate removal, pass 2 Fri Dec 25 20:41:20 2009 found 771129 duplicates and 7725955 unique relations <snip> Fri Dec 25 20:46:42 2009 matrix is 636031 x 636258 (183.2 MB) with weight 47730814 (75.02/col) Fri Dec 25 20:46:42 2009 sparse part has weight 41667595 (65.49/col) Fri Dec 25 20:46:42 2009 matrix includes 64 packed rows Fri Dec 25 20:46:42 2009 using block size 65536 for processor cache size 4096 kB Fri Dec 25 20:46:46 2009 commencing Lanczos iteration (2 threads) Fri Dec 25 20:46:46 2009 memory use: 181.3 MB Fri Dec 25 20:46:54 2009 linear algebra at 0.2%, ETA 0h55m Fri Dec 25 21:46:41 2009 lanczos halted after 10061 iterations (dim = 636028) Fri Dec 25 21:46:43 2009 recovered 27 nontrivial dependencies Fri Dec 25 21:46:43 2009 BLanczosTime: 3718 Fri Dec 25 21:46:43 2009 Fri Dec 25 21:46:43 2009 commencing square root phase Fri Dec 25 21:46:43 2009 reading relations for dependency 1 Fri Dec 25 21:46:43 2009 read 317038 cycles Fri Dec 25 21:46:44 2009 cycles contain 1023738 unique relations Fri Dec 25 21:46:58 2009 read 1023738 relations Fri Dec 25 21:47:06 2009 multiplying 1023738 relations Fri Dec 25 21:50:41 2009 multiply complete, coefficients have about 44.49 million bits Fri Dec 25 21:50:42 2009 initial square root is modulo 2443927 Fri Dec 25 21:57:45 2009 sqrtTime: 662 Fri Dec 25 21:57:45 2009 prp49 factor: 1614394407529950231948689326128270361414761568603 Fri Dec 25 21:57:45 2009 prp73 factor: 2442331971867286584011502653002290013163478345321068635697408534391895789 Fri Dec 25 21:57:45 2009 elapsed time 01:18:35 Edit: If I see correctly, the factors are 1 mod 3.
Last fiddled with by Andi47 on 2009-12-25 at 21:13 |
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#665 |
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Nov 2008
2×33×43 Posts |
The 3 has disappeared again!
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#666 |
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Oct 2004
Austria
9B216 Posts |
DB is up again, and I see that someone seems to have clicked Quick-ECM - we now have a c161, and the sequence got rid of the 3 *very* quick
Code:
2495. 221665515240712835146632915038654332249677600521866315490705901031882614988052048857984072398217318255693431659468618236169689657416113688944691446324158756073966101682032 = 2^4 * 3559 * 220681 * 592772569 * 7547146554874360724158181221231 * 1614394407529950231948689326128270361414761568603 * 2442331971867286584011502653002290013163478345321068635697408534391895789 2496. 207934041439159666402719289421731533248712421461988300495417637950528851328183231602527567551285460133911968968270227215739684980733388937486979959359115607573614923085968 = 2^4 * 3^3 * 317 * 757 * 50924647 * 3088726995612795721 * 12752024987120885573855872723202403795026326832056826089540602758711687497126775191275849808610417125744238645554854915822786087517285333 2497. 391587407602724606683481473757692838731899590545814526536499415906443230131930260643701621866514302532389288790656571729396302031661198446031414125384098925446994919996272 = 2^4 * 3 * 83257 * 97986607633273229949504114208037772282385562811989413937291412910837134348045374724172747703525004537253446354524887729509306032240832213815708720534033906420029477 2498. 620025545710327153129359405293175458009270700840661687036785632653736058180215403645660032042696216110178993345887532990955937370744895402744252179739502852162138050639904 = 2^5 * 61 * 10404019 Last fiddled with by Andi47 on 2009-12-25 at 21:37 |
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#667 |
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"Robert Gerbicz"
Oct 2005
Hungary
2·743 Posts |
now only c134:
Code:
Using B1=1000000, B2=1045563762, polynomial Dickson(6), sigma=2243524066 Step 1 took 18205ms Step 2 took 12262ms ********** Factor found in step 2: 1053510145349455459655189063 Found probable prime factor of 28 digits: 1053510145349455459655189063 Composite cofactor 2897943480588228707823873533626392259113337697364013323014773796420074066675329471987609206871621029590 2512926053853268268773796067441 has 134 digits |
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#668 |
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"Robert Gerbicz"
Oct 2005
Hungary
2·743 Posts |
Killed.
Code:
Run 45 out of 948: Using B1=1000000, B2=1045563762, polynomial Dickson(6), sigma=2841086046 Step 1 took 13931ms Step 2 took 9625ms ********** Factor found in step 2: 275672488609181335964910240943 Found probable prime factor of 30 digits: 275672488609181335964910240943 Probable prime cofactor 10512269451365601486564964719249900397856401577901033520503299884146118828035871491891733785832743 0257887 has 105 digits |
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#669 |
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Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
17×251 Posts |
Index 2501 has a c166. No idea how much ECM so far, but I've clicked two Quick ECMs.
Last fiddled with by Mini-Geek on 2009-12-25 at 22:11 |
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#670 |
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"Robert Gerbicz"
Oct 2005
Hungary
101110011102 Posts |
Factored.
Code:
Using B1=1000000, B2=1045563762, polynomial Dickson(6), sigma=843301289 Step 1 took 18580ms Step 2 took 12230ms ********** Factor found in step 2: 21576911035234107060567359 Found probable prime factor of 26 digits: 21576911035234107060567359 Probable prime cofactor 27324997159006699095076661613314836247165012351115938582637324350291992335079286058776193292444980 2628020051974483243245518676185344336490951 has 141 digits |
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#671 |
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"Robert Gerbicz"
Oct 2005
Hungary
101110011102 Posts |
Another easy goal on line 2502:
Code:
Using B1=1000000, B2=1045563762, polynomial Dickson(6), sigma=2863442735 Step 1 took 15163ms Step 2 took 10280ms ********** Factor found in step 2: 62867187091895665602431325293 Found probable prime factor of 29 digits: 62867187091895665602431325293 Probable prime cofactor 10388219128879144885656371803679068375540698889290568480135606623289797480435783087640389370988520 407960455115608852781 has 119 digits Last fiddled with by R. Gerbicz on 2009-12-25 at 22:32 |
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