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Old 2009-12-24, 13:29   #661
10metreh
 
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Quote:
Originally Posted by Raman View Post
To come up to a conclusion, the next iteration will acquire up the factor 3 if and only if
the c121 splits up into two (1 mod 3) factors.
Does not pick up a 3, when the c121 splits up into two (2 mod 3) factors.

Right, man?
Correct.
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Old 2009-12-24, 13:51   #662
Raman
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Quote:
Originally Posted by 10metreh View Post
Correct.
Meanwhile, pray up to God that it splits up into two (2 mod 3) factors

I wonder whether you check up the residue class of each factor of each iteration mod 3, 5, 7...?

Once it acquires up a factor of 3, in order to lose it up:
s(c) = product of (1+p)'s - c.
(1+p) is replaced up by (1+p+p2+...) for the prime powers...

Since c is divisible by 3, in order to lose the 3, the products of (1+p)'s should be 1 or 2 mod 3. The factor of 3 will not stimulate again a 3 in the next line at all, since (1+3+9+...) is always equal to 1 mod 3.

Any of the others should not be divisible by 3 at all.
A prime of 2 mod 3, will induce up a 3 in the next line by using (1+p)
A prime of 1 mod 3, will not.
However, that all of the primes other than 3, cannot be equal to 0 mod 3, anyway.

For the prime powers, power of 2 mod 3 will trigger up a 3 if the power is odd. Power of 1 mod 3 will trigger 3, if the power is even.

I see that it can lose up the 3 within the next iteration, if for all the primes besides 3, the power of 2 mod 3 primes are all even, and then the power of 1 mod 3 primes are all odd.
Or, in fact it is true that it can lose up the 3 within the subsequent iterations by means of using the factor of 9 = 32

All these are natural processes only, by itself. We can't do anything to change sequences, or write up a random number of our own. We just simply compute the results, and then go on processing with the single correct number of the next iteration.

Last fiddled with by Raman on 2009-12-24 at 13:52
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Old 2009-12-24, 21:37   #663
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Quote:
Originally Posted by Andi47 View Post
Thanks. I will do a p-1 followed by GNFS

edit: started p-1 and polsel in parallel
p-1 to B1=1e9, B2=1e15 and 3* p+1 to B1=1e9, B2=1e15: no factor. Starting GNFS...
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Old 2009-12-25, 21:01   #664
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Default c121 factored

Code:
Fri Dec 25 20:39:10 2009  
Fri Dec 25 20:39:10 2009  
Fri Dec 25 20:39:10 2009  Msieve v. 1.43
Fri Dec 25 20:39:10 2009  random seeds: e4aca9c8 a1f403b9
Fri Dec 25 20:39:10 2009  factoring 3942887076714143202481073805784961368619711215403426727623016228578779996971144714931046107405659926915911799176550312767 (121 digits)
Fri Dec 25 20:39:12 2009  no P-1/P+1/ECM available, skipping
Fri Dec 25 20:39:12 2009  commencing number field sieve (121-digit input)
Fri Dec 25 20:39:12 2009  R0: -220525782874300519278221
Fri Dec 25 20:39:12 2009  R1:  10561525245991
Fri Dec 25 20:39:12 2009  A0:  13919992851438837656957797344
Fri Dec 25 20:39:12 2009  A1: -7900337548465327330903242
Fri Dec 25 20:39:12 2009  A2:  14318233152048859923
Fri Dec 25 20:39:12 2009  A3: -542592852133532
Fri Dec 25 20:39:12 2009  A4: -1569762856
Fri Dec 25 20:39:12 2009  A5:  7560
Fri Dec 25 20:39:12 2009  skew 191636.60, size 1.651620e-11, alpha -6.880605, combined = 2.901254e-10
Fri Dec 25 20:39:12 2009  
Fri Dec 25 20:39:12 2009  commencing relation filtering
Fri Dec 25 20:39:12 2009  estimated available RAM is 1985.8 MB
Fri Dec 25 20:39:12 2009  commencing duplicate removal, pass 1
Fri Dec 25 20:39:28 2009  error -15 reading relation 1477379
Fri Dec 25 20:39:48 2009  error -15 reading relation 3405784
Fri Dec 25 20:40:45 2009  found 1083950 hash collisions in 8438938 relations
Fri Dec 25 20:41:14 2009  added 58146 free relations
Fri Dec 25 20:41:14 2009  commencing duplicate removal, pass 2
Fri Dec 25 20:41:20 2009  found 771129 duplicates and 7725955 unique relations

<snip>

Fri Dec 25 20:46:42 2009  matrix is 636031 x 636258 (183.2 MB) with weight 47730814 (75.02/col)
Fri Dec 25 20:46:42 2009  sparse part has weight 41667595 (65.49/col)
Fri Dec 25 20:46:42 2009  matrix includes 64 packed rows
Fri Dec 25 20:46:42 2009  using block size 65536 for processor cache size 4096 kB
Fri Dec 25 20:46:46 2009  commencing Lanczos iteration (2 threads)
Fri Dec 25 20:46:46 2009  memory use: 181.3 MB
Fri Dec 25 20:46:54 2009  linear algebra at 0.2%, ETA 0h55m
Fri Dec 25 21:46:41 2009  lanczos halted after 10061 iterations (dim = 636028)
Fri Dec 25 21:46:43 2009  recovered 27 nontrivial dependencies
Fri Dec 25 21:46:43 2009  BLanczosTime: 3718
Fri Dec 25 21:46:43 2009  
Fri Dec 25 21:46:43 2009  commencing square root phase
Fri Dec 25 21:46:43 2009  reading relations for dependency 1
Fri Dec 25 21:46:43 2009  read 317038 cycles
Fri Dec 25 21:46:44 2009  cycles contain 1023738 unique relations
Fri Dec 25 21:46:58 2009  read 1023738 relations
Fri Dec 25 21:47:06 2009  multiplying 1023738 relations
Fri Dec 25 21:50:41 2009  multiply complete, coefficients have about 44.49 million bits
Fri Dec 25 21:50:42 2009  initial square root is modulo 2443927
Fri Dec 25 21:57:45 2009  sqrtTime: 662
Fri Dec 25 21:57:45 2009  prp49 factor: 1614394407529950231948689326128270361414761568603
Fri Dec 25 21:57:45 2009  prp73 factor: 2442331971867286584011502653002290013163478345321068635697408534391895789
Fri Dec 25 21:57:45 2009  elapsed time 01:18:35
I can't post the factors to the DB right now - DB seems to be down.

Edit: If I see correctly, the factors are 1 mod 3.

Last fiddled with by Andi47 on 2009-12-25 at 21:13
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Old 2009-12-25, 21:34   #665
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The 3 has disappeared again!
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Old 2009-12-25, 21:37   #666
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DB is up again, and I see that someone seems to have clicked Quick-ECM - we now have a c161, and the sequence got rid of the 3 *very* quick

Code:
2495.   221665515240712835146632915038654332249677600521866315490705901031882614988052048857984072398217318255693431659468618236169689657416113688944691446324158756073966101682032 = 2^4 * 3559 * 220681 * 592772569 * 7547146554874360724158181221231 * 1614394407529950231948689326128270361414761568603 * 2442331971867286584011502653002290013163478345321068635697408534391895789
2496.   207934041439159666402719289421731533248712421461988300495417637950528851328183231602527567551285460133911968968270227215739684980733388937486979959359115607573614923085968 = 2^4 * 3^3 * 317 * 757 * 50924647 * 3088726995612795721 * 12752024987120885573855872723202403795026326832056826089540602758711687497126775191275849808610417125744238645554854915822786087517285333
2497.   391587407602724606683481473757692838731899590545814526536499415906443230131930260643701621866514302532389288790656571729396302031661198446031414125384098925446994919996272 = 2^4 * 3 * 83257 * 97986607633273229949504114208037772282385562811989413937291412910837134348045374724172747703525004537253446354524887729509306032240832213815708720534033906420029477
2498.   620025545710327153129359405293175458009270700840661687036785632653736058180215403645660032042696216110178993345887532990955937370744895402744252179739502852162138050639904 = 2^5 * 61 * 10404019
Edit: 10metreh was faster.

Last fiddled with by Andi47 on 2009-12-25 at 21:37
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Old 2009-12-25, 21:56   #667
R. Gerbicz
 
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now only c134:
Code:
Using B1=1000000, B2=1045563762, polynomial Dickson(6), sigma=2243524066
Step 1 took 18205ms
Step 2 took 12262ms
********** Factor found in step 2: 1053510145349455459655189063
Found probable prime factor of 28 digits: 1053510145349455459655189063
Composite cofactor 2897943480588228707823873533626392259113337697364013323014773796420074066675329471987609206871621029590
2512926053853268268773796067441 has 134 digits
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Old 2009-12-25, 22:05   #668
R. Gerbicz
 
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Killed.
Code:
Run 45 out of 948:
Using B1=1000000, B2=1045563762, polynomial Dickson(6), sigma=2841086046
Step 1 took 13931ms
Step 2 took 9625ms
********** Factor found in step 2: 275672488609181335964910240943
Found probable prime factor of 30 digits: 275672488609181335964910240943
Probable prime cofactor 10512269451365601486564964719249900397856401577901033520503299884146118828035871491891733785832743
0257887 has 105 digits
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Old 2009-12-25, 22:10   #669
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Index 2501 has a c166. No idea how much ECM so far, but I've clicked two Quick ECMs.

Last fiddled with by Mini-Geek on 2009-12-25 at 22:11
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Old 2009-12-25, 22:15   #670
R. Gerbicz
 
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Factored.
Code:
Using B1=1000000, B2=1045563762, polynomial Dickson(6), sigma=843301289
Step 1 took 18580ms
Step 2 took 12230ms
********** Factor found in step 2: 21576911035234107060567359
Found probable prime factor of 26 digits: 21576911035234107060567359
Probable prime cofactor 27324997159006699095076661613314836247165012351115938582637324350291992335079286058776193292444980
2628020051974483243245518676185344336490951 has 141 digits
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Old 2009-12-25, 22:31   #671
R. Gerbicz
 
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Another easy goal on line 2502:
Code:
Using B1=1000000, B2=1045563762, polynomial Dickson(6), sigma=2863442735
Step 1 took 15163ms
Step 2 took 10280ms
********** Factor found in step 2: 62867187091895665602431325293
Found probable prime factor of 29 digits: 62867187091895665602431325293
Probable prime cofactor 10388219128879144885656371803679068375540698889290568480135606623289797480435783087640389370988520
407960455115608852781 has 119 digits

Last fiddled with by R. Gerbicz on 2009-12-25 at 22:32
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