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Old 2009-01-22, 20:36   #1
davieddy
 
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"Lucan"
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Default Best countdown problem ever

100, 75, 50, 25, 11, 1
Target 278

(Use simple arithmetic on the the six numbers)
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Old 2009-01-22, 20:40   #2
10metreh
 
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Quote:
Originally Posted by davieddy View Post
100, 75, 50, 25, 11, 1
Target 278

(Use simple arithmetic on the the six numbers)
When was 11 allowed in Countdown?
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Old 2009-01-22, 21:01   #3
Flatlander
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(11*25) + (100/50) + 1
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Old 2009-01-22, 21:22   #4
lavalamp
 
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Is it ... the final countdown?

I assume you meant another 1 there instead of 11.

100/25 = 4
50 + 1 = 51

4 * 51 = 204
75 - 1 = 74

204 + 74 = 278

Last fiddled with by lavalamp on 2009-01-22 at 21:22
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Old 2009-01-22, 21:33   #5
mart_r
 
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Me gots a solution:

11*25+(100+50)/75+1

Puzzling time: < 10 mins

Last fiddled with by mart_r on 2009-01-22 at 21:33
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Old 2009-01-23, 00:45   #6
jrk
 
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(75/25-1)*(100+50-11)
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Old 2009-01-23, 08:46   #7
Mr. P-1
 
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I got Flatlanders solution to the problem as posed.

If the 11 is replaced by 1 then my solution is

(50 / 25) * (100 + 1) + 75 + 1
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Old 2009-01-23, 10:30   #8
davieddy
 
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I don't know why my genrally trustworthy source
deemed this such a good puzzle.

I have received a correction:

The numbers are supposed to be 25 50 75 100 10 1
Target 278

Last fiddled with by davieddy on 2009-01-23 at 10:46
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Old 2009-01-23, 12:32   #9
10metreh
 
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Quote:
Originally Posted by davieddy View Post
I don't know why my genrally trustworthy source
deemed this such a good puzzle.

I have received a correction:

The numbers are supposed to be 25 50 75 100 10 1
Target 278
(75*100-((10+1)*50))/25=278
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Old 2009-01-23, 14:35   #10
davieddy
 
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Quote:
Originally Posted by 10metreh View Post
(75*100-((10+1)*50))/25=278
Assuming you are right (and I haven't checked) well done
and the author of the problem is redeemed

David

Last fiddled with by davieddy on 2009-01-23 at 14:35
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Old 2009-01-23, 23:51   #11
mart_r
 
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Also,

(75/25-(10+1)/50)*100=278
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