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#1 |
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Dec 2008
you know...around...
12278 Posts |
Hello again,
some time ago I noticed that there seems to be a strange connection between the standard normal distribution and 1/tanh(pi^2), as to be seen in A133658 in the OEIS: http://www.research.att.com/~njas/sequences/A133658 I wondered if any of you are able to tell me what's going on with these numbers. Last fiddled with by mart_r on 2009-01-18 at 13:21 |
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#2 |
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Dec 2008
you know...around...
3×13×17 Posts |
Is this even interesting? A coincidence? Or is it a trivial phenomenon?
Last fiddled with by mart_r on 2009-01-25 at 15:55 |
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#3 |
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Nov 2008
2·33·43 Posts |
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#4 |
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Dec 2008
you know...around...
3×13×17 Posts |
Had a look into this again today and found:
1/tanh(pi²) = 1 + 2*[e^(-2pi²)+e^(-4pi²)+e^(-6pi²)+e^(-8pi²)+...] (rather easy) A133658 __= 1 + 2*[e^(-2pi²)+e^(-8pi²)+e^(-18pi²)+e^(-32pi²)+e^(-50pi²)+...] (rather interesting) I would try to figure out why this is so, if only I could find an explanation of how the factor of 1/sqrt(2pi) in the standard normal distribution comes about... (Come think of it, this thread should probably be moved to Math or MiscMath) Last fiddled with by mart_r on 2009-10-22 at 18:16 |
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#5 |
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"Lucan"
Dec 2006
England
647410 Posts |
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#6 |
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Dec 2008
you know...around...
3·13·17 Posts |
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#7 |
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"Lucan"
Dec 2006
England
2·3·13·83 Posts |
Hint:
Find the volume under the surface e^-a(x^2 + y^2) Don't spoil the fun by googling
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#8 |
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Dec 2008
you know...around...
3×13×17 Posts |
Assuming a sphere (which I guess is the wrong way, right?),
e^(-3a(x²+y²)/2)/6pi^(3/2) (is there something like an instruction for use of the TEX-format?) Last fiddled with by mart_r on 2009-10-24 at 19:41 |
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#9 | |
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"Lucan"
Dec 2006
England
2×3×13×83 Posts |
Quote:
as I do on paper. z = e^-a(x^2 + y^2) is the surface Find the the volume between it and the whole plane z=0. PS Pythagoras comes in handy. Last fiddled with by davieddy on 2009-10-24 at 20:30 |
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#10 |
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Account Deleted
"Tim Sorbera"
Aug 2006
San Antonio, TX USA
17·251 Posts |
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#11 | |
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Dec 2008
you know...around...
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Quote:
(z is the surface? I thought it was the room coordinate?) Maybe I'd figure it out eventually, but not today. @ Mini-Geek: thanks! Last fiddled with by mart_r on 2009-10-25 at 11:12 |
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