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#1112 |
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Sep 2010
Scandinavia
3·5·41 Posts |
You're not making much sense.
Do the translation before you post. Hopefully that will help. If you're saying that you're adding all prime numbers, let's get some perspective; Right now the db contains about 4.6*10^8 numbers, which is roughly equal to the number of primes 9 digits or smaller. Edit: I tried... Wont bother with this anymore. Last fiddled with by lorgix on 2011-05-25 at 12:28 |
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#1113 | |
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Mar 2006
479 Posts |
Quote:
My question is, what is your goal? Are you trying to factor numbers of a certain form? Are you trying to find numbers with a certain property? If you are trying to factor numbers of a special form, I'd recommend using either yafu or msieve. They are both excellent programs. This way, you can continue your mathematical activities without putting a burden on the factordb. If you need help running/using either yafu or msieve, you can open a new thread where we can answer your questions. In any case, I'd like to ask you to stop using the factordb like you are currently using it. |
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#1114 |
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Sep 2008
Kansas
3,389 Posts |
Code:
mysql> select digits, count(digits) as n from C where digits<100 group by digits having n>10; Last fiddled with by RichD on 2011-05-25 at 15:03 Reason: strike Status |
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#1115 | |
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Sep 2008
Krefeld, Germany
111001102 Posts |
Quote:
http://factordb.com/stat_1.php The query is fast, there's no need to cache it. Btw, left the n>10 out
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#1116 | ||
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"Frank <^>"
Dec 2004
CDP Janesville
2×1,061 Posts |
Quote:
Quote:
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#1117 | |
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"Frank <^>"
Dec 2004
CDP Janesville
2·1,061 Posts |
Quote:
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#1118 |
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"Frank <^>"
Dec 2004
CDP Janesville
2×1,061 Posts |
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#1119 |
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Sep 2010
Scandinavia
61510 Posts |
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#1120 |
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Sep 2010
Scandinavia
3·5·41 Posts |
Looking at HP10(49) I clicked 'Show huge graph'.
That brought me to http://factordb.com/aliquot.php?type=10&aq=7&big=1 And this image was displayed; |
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#1121 |
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Sep 2010
Scandinavia
3×5×41 Posts |
Seems like someone just put a few thousand RSA-1024 into the db...
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#1122 |
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"William"
May 2003
New Haven
2·7·132 Posts |
Why is there interest in finding the complete factorization of 136^35+n for n odd 1 to one million, and 2^1024+n, n 1 to 1000? It appears both of these sets have been dumped into factordb this week.
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