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#870 |
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Nov 2009
2×52×7 Posts |
I would like to reserve R75 to n=100K
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#871 |
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May 2007
Kansas; USA
2×41×127 Posts |
Reserving R36 to n=100K.
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#872 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
949710 Posts |
2186*7^739474-1 says that R49 is proven.
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#873 |
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May 2007
Kansas; USA
2×41×127 Posts |
Nuggetprime reported in an Email that S42 is complete to n=50K; 11 previously reported primes were found for n=25K-50K; 32 k's remain; the base is released.
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#874 |
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May 2007
Kansas; USA
2·41·127 Posts |
Reserving S42, S45, and S46 to n=100K.
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#875 |
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"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
9,497 Posts |
I will take S49 to n=250K and S87 to n=300K.
Last fiddled with by Batalov on 2011-06-02 at 07:59 |
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#876 |
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May 2008
Wilmington, DE
22·23·31 Posts |
A status update for S51 ck=5,183,582
k's 0M-1M tested to n=25K (complete) k's 1M-3M tested to n=17K (currently being tested n=17K to 25K) k's 3M-5M+ tested to n-17K (currently being sieved n=17K to 25K) 11.5M tests have been run ~ 2.1M tests still to run I'm guessing ~7200k's will be remaining @ n=25K Gary, I'm sending you 3 files of primes. We should be 100% complete on all k's to n=17K and 100% done on 0M-1M k's to n=25K. 0M-1M 14K-25K 1M-3M 12K-17K 3M-5M 10K-17K If I have missed sending you something, let me know. Note: This has mostly been done on a laptop with 2 cores and all the sieving done on an atom AM I BORED YET? Last fiddled with by MyDogBuster on 2011-06-03 at 19:26 |
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#877 |
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May 2007
Kansas; USA
2·41·127 Posts |
Oh good gawd. I'm not looking forward to this.
Can you balance all of the k's remaining, do the web pages changes for me, and send the HTML to me?
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#878 | |
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May 2008
Wilmington, DE
22·23·31 Posts |
Quote:
![]() A nice job with a beer and some nachos. LOL |
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#879 | |
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May 2007
Kansas; USA
2·41·127 Posts |
Quote:
There were 10081 k's remaining at n=10K. There were 675 k's found prime for k<=1M for n=10K-25K. There were 775 k's found prime for k=1M-3M for n=10K-17K. There were 882 k's found prime for k=3M-5.183M for n=10K-17K. Total of 2332 k's found prime for the range. There are 10081 - 2332 = 7749 k's remaining at n=25K for k<=1M and n=17K for k>1M. |
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#880 | |
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May 2008
Wilmington, DE
22·23·31 Posts |
Quote:
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