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#320 |
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May 2007
Kansas; USA
101·103 Posts |
Riesel base 95 is at n=14K; 21 k's remain; continuing to n=25K
Sierp base 61 is complete to n=25K; 18 k's remain; now unreserved I will start on new Sierp base 88 is the next couple of days; going to n=25K. After that, only Riesel and Sierp base 46 to go. I may reserve new Sierp base base 60 up to n=25K after all of that is done. I haven't decided yet. Besides Sierp base 88, it is the last remaining base <= 100 that is likely to have < 50 k's remaining at n=10K. Gary |
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#321 |
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May 2007
Kansas; USA
101·103 Posts |
Riesel base 95 is at n=21K; 20 k's remain; continuing to n=25K.
Sierp base 88 is at n=10K; 25 k's remain; continuing to n=25K. Next is Riesel and Sierp bases 46 to n=25K to complete current reservations. New reservation: Sierp base 60 to n=25K. Last fiddled with by gd_barnes on 2009-06-19 at 06:38 |
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#322 |
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"Mark"
Apr 2003
Between here and the
11000110100002 Posts |
84977*58^23007-1
92229*58^23283-1 79011*58^23299-1 40808*58^23805-1 63177*58^24402-1 58086*58^24630-1 17876*58^24838-1 27861*58^24850-1 24320*58^24879-1 Completed to 25000 and continuing |
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#323 |
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May 2007
Kansas; USA
242438 Posts |
Sierp base 88 is at n=15K; 20 k's remain; continuing to n=25K.
Riesel base 95 is complete to n=25K; 19 k's remain; now unreserved. Sierp base 60 and both sides of base 46 to go for my reservations for bases > 32. |
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#324 |
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May 2007
Kansas; USA
28A316 Posts |
Sierp base 88 is complete to n=25K; 18 k's remain; now unreserved
Sierp base 60 is at n=5K; 65 k's remain; continuing to n=25K; status to be shown on web pages at n>=10K when fewer k's remain. Riesel and Sierp base 46 have just completed sieving n=10K-25K. I'll test them concurrently. |
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#325 |
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A Sunny Moo
Aug 2007
USA (GMT-5)
3·2,083 Posts |
Reserving Riesel base 94 up to n=60K.
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#326 |
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"Mark"
Apr 2003
Between here and the
143208 Posts |
11484*58^25101-1
97164*58^25107-1 92712*58^25155-1 30612*58^25160-1 67547*58^25190-1 56841*58^25370-1 35774*58^25389-1 13682*58^25551-1 51894*58^25995-1 81114*58^26065-1 85617*58^26280-1 49146*58^26334-1 33266*58^26463-1 11538*58^26541-1 80579*58^26592-1 80180*58^26646-1 58314*58^26877-1 91766*58^26879-1 28008*58^26894-1 39684*58^27023-1 53636*58^27438-1 41469*58^27517-1 48156*58^27521-1 14396*58^27614-1 32118*58^27826-1 19854*58^28071-1 90279*58^28112-1 104724*58^28404-1 71598*58^28680-1 101715*58^28702-1 Completed to 29000 and continuing. If I have counted correctly, there are 360 remaining k. |
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#327 |
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A Sunny Moo
Aug 2007
USA (GMT-5)
3·2,083 Posts |
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#328 |
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A Sunny Moo
Aug 2007
USA (GMT-5)
3×2,083 Posts |
Riesel base 94 is complete to n=70K; releasing this base. Results are attached for 51K-70K.
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#329 |
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A Sunny Moo
Aug 2007
USA (GMT-5)
141518 Posts |
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#330 |
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May 2007
Kansas; USA
101×103 Posts |
For Riesel base 58, after adjusting for one k that already had a prime, there were 408 k's remaining at n=21K per my note in a prior post. k's found prime for:
n=21K-22K; 8 n=22K-23K; 3 n=23K-24K; 4 n=24K-25K; 5 n=25K-26K; 9 n=26K-27K; 10 n=27K-28K; 6 n=28K-29K; 4 (k=19854 already had a prime at n=13287) Total k's with primes for n=21K-29K: 49 Total k's remaining at n=29K: 408 - 49 = 359. This also balances with the k's I show remaining on the web page. So somewhere you are off by 1. If you erroneously subtracted off k=19854 (or some other k) twice as a result of finding 2 primes for it and now have to add it back, you would be off by 2 so the error must be somewhere else. You might check your k's remaining against my web page as well as remove k's with former primes like k=19854 from your sieve file to avoid any possible future confusion in that regard. I do a balancing every time I remove k's from the Riesel base 58 reservations web page. |
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