20120926, 13:15  #34 
P90 years forever!
Aug 2002
Yeehaw, FL
2·7·563 Posts 
FermatFactor=56,200e12,1e15
FermatFactor=57,280e12,1e15 FermatFactor=58,280e12,1e15 FermatFactor=59,280e12,1e15 
20120927, 17:37  #35 
Jul 2003
So Cal
100100111000_{2} Posts 
FermatFactor=60,2e14,1e15

20120928, 19:32  #36 
Apr 2012
993438: i1090
2×73 Posts 
FermatFactor=61,200e12,1e15
FermatFactor=62,200e12,1e15 
20120929, 00:27  #37 
Jul 2003
So Cal
2^{3}×5×59 Posts 
FermatFactor=63,2e14,1e15

20120929, 01:48  #38 
Jul 2003
1146_{8} Posts 
FermatFactor=94,200e12,1000e12
FermatFactor=95,200e12,1000e12 
20120929, 19:35  #39 
"Åke Tilander"
Apr 2011
Sandviken, Sweden
2×283 Posts 
MM127
MMFactor=127,4300e12,4600e12

20120929, 20:58  #40 
Jul 2003
2·307 Posts 
MMFactor=31,18014398509481982,20e15

20120930, 06:08  #41 
Einyen
Dec 2003
Denmark
7×11×43 Posts 

20120930, 07:00  #42 
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
7×23×61 Posts 
I noticed that later. (It depends on the k value; for lower k ranges, it would have run). I am running the early 140s now.
I will probably fiddle, later. (Now that my hands are untied from PE 396, heh, heh, nice one, btw..!) The same limit kicks in for the mmffgfn and I did want to extend the upper limit for both. The main driver of the probability of success is simply ~ 1/k !* (~ 1/k * 1/(ln k + N ln 2), but the last part is soooo flat), so getting to as low k as possible is desirable. ;) *! is not the factorial sign, surely Last fiddled with by Batalov on 20120930 at 07:02 Reason: 1/k! would have been silly 
20120930, 20:01  #43 
Jul 2003
So Cal
938_{16} Posts 
FermatFactor=71,3e14,1e15

20121001, 01:32  #44 
Aug 2010
Kansas
547 Posts 
FermatFactor=100,4e12,145

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