20171228, 07:35  #45 
May 2017
ITALY
2·3^{2}·29 Posts 

20171228, 07:40  #46 
Romulan Interpreter
"name field"
Jun 2011
Thailand
23351_{8} Posts 

20171228, 08:34  #47 
May 2017
ITALY
2·3^{2}·29 Posts 

20171228, 11:48  #48 
May 2017
ITALY
2·3^{2}·29 Posts 

20171230, 09:43  #49 
May 2017
ITALY
1012_{8} Posts 
The algorithm that I show you is in X with repetitions, if you want to apply the variant of log_2, you will have X * log_2 () with X without repetitions.
For Z we are interested if you admit solutions or not For others we must test whether the parent's product difference is the same but opposite sign from that of the child Example CHECK Z [11357932*a^2]=Z , Z=a*(an) , a^2+n*a=1135793 YES solution bad way , Z is positive [11357932*a^2]=Z , Z=a*(an) , a^2+n*a=1135793 NO solution good way CHECK Q [11357932*a^2]=Z , Z=a*(an), Z2*(a)^2=[a*[(a)((an)(a))]]=A , a^2+n*a=1135793 [11357932*a^2]=Z , Z=a*(an), Z2*(an)^2=[((an))*[(an)(a((an)))]]=B , a^2+n*a=1135793 [[(a)((an)(a))]a]=((an)(a)) , a^2+n*a=1135793 There are no solutions are different then Q = A [a*[(a)((an)(a))]]=a*((3*an))=Q CHECK R Q2*a^2=[a*((3*an))]2*a^2=[a*[a((3*an)a)]]=A , a^2+n*a=1135793 Q2*((3*an))^2=[((3*an))*[((3*an))(a((3*an)))]]=B , a^2+n*a=1135793 [[a((3*an)a)]a]=[[(a)((an)(a))]a] , a^2+n*a=1135793 There are no solutions are different then R = A [a*[a((3*an)a)]]=a*(5*a+n)=R CHECK T R2*a^2=[a*[a((5*a+n)a)]]=A , a^2+n*a=1135793 R2*(5*a+n)^2=[(5*a+n)*[(5*a+n)(a(5*a+n))]]=B , a^2+n*a=1135793 [(5*a+n)a]=[[a((5*a+n)a)]a] , a^2+n*a=1135793 TRUE they are the same, better to say they are opposite then T = B [(5*a+n)*[(5*a+n)(a(5*a+n))]]=(5*a+n)*(11*a+2*n)=T etc.etc. Does anyone confirm me the accuracy of the algorithm? 
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