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 2009-05-13, 08:02 #1 Andi47     Oct 2004 Austria 2·17·73 Posts please help with an integral How do I integrate the following functions - I somehow don't see the trick...? a.) integrate (2x² - 3x - 4) /(3x-5) dx b.) integrate (4x² - 6x + 2)² * (3x - 5) / 2x³ dx
 2009-05-13, 08:10 #2 Batalov     "Serge" Mar 2008 Phi(4,2^7658614+1)/2 268016 Posts Hmm... a. Divide, and you will get something like ax+b+c/(3x-5) which will become easy. b. Probably, the easiest to do the same as a.
 2009-05-13, 14:09 #3 Mr. P-1     Jun 2003 7·167 Posts b: Multiply out the numerator and divide term by term by the denominator. The result will be a sum of +ve and -ve powers of x, plus a constant, which can be integrated term by term. a. Do the substitution u = 3x - 5 then proceed as above. Last fiddled with by Mr. P-1 on 2009-05-13 at 14:09
2009-05-13, 17:49   #4
Andi47

Oct 2004
Austria

9B216 Posts

Quote:
 Originally Posted by Mr. P-1 b: Multiply out the numerator and divide term by term by the denominator. The result will be a sum of +ve and -ve powers of x, plus a constant, which can be integrated term by term. a. Do the substitution u = 3x - 5 then proceed as above.
Thanks! Seems I've been somewhat out of practice...

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