20131116, 09:47  #47  
Mar 2010
192_{10} Posts 
Quote:
If you are doing this what you adviced me to do then DON'T DO SO!. Find area interesting for you and unsolved problem interesting for you and try to solve it. People will tell you that your work is worthless and this is what they will think. It is because everybody thinks that only his area of interest is worthy to pay attentions. 

20131116, 11:08  #48  
"(^r'°:.:)^n;e'e"
Nov 2008
;t:.:;^
1111100111_{2} Posts 
imo
Quote:
but It also 

20131116, 15:39  #49 
Jun 2003
37·131 Posts 
@Literka: After step 10, you should b multiplying by 512, not 256.

20131116, 16:00  #50 
Romulan Interpreter
Jun 2011
Thailand
9,161 Posts 
What?? After all this fight, you want to say that he has a mistake in that beautiful demonstration?
(read as: did you actually wasted the time to click and read? man, you must be really free and bored! I may change my opinion about you... ) 
20131116, 16:19  #51 
Mar 2010
2^{6}×3 Posts 

20131116, 17:21  #52 
"Jane Sullivan"
Jan 2011
Beckenham, UK
EE_{16} Posts 
I am amazed that so much has been written in this thread about the factorization of F7. As far as I am concerned you pass the number into YAFU, wait a short while, and pick up the factors out the other end. End of story, pass on to the next number.
Since you will have done this one a few years ago, with all the others you will have done in the meantime you should be looking at F77 now, or even F777, and certainly not F7. Last fiddled with by BudgieJane on 20131116 at 17:22 Reason: Correction of grammatical error. 
20131116, 17:32  #53  
Mar 2010
2^{6}·3 Posts 
Quote:
Yes, it is a wonderful idea. I waited less than 1 sec. for a result. Quote:
I don't like number 7. I would better do F88. 

20131116, 19:27  #54 
Aug 2010
Kansas
547 Posts 
F88 would take too long to write out manually. Might I suggest F20 instead? Its a nice, round number, and much smaller :)
If you make any usable* progress, I will pay your website's hosting costs for a year. *Usable progress will be determined and prizes awarded at the discretion of the challenge creator. 
20131116, 20:03  #55  
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
2^{4}·3·193 Posts 
Quote:
Even this is no longer true. You didn't even have a proof until Anand Nair corrected you. 

Thread Tools  
Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
On Fermat's Last Number  c10ck3r  Miscellaneous Math  14  20121129 20:36 
Fermat number F6=18446744073709551617 is a composite number. Proof.  literka  Factoring  5  20120130 12:28 
Fermat number and Modulo for searching divisors  CyD  Factoring  4  20110531 11:24 
Fermat number factors  Citrix  Math  35  20070123 23:17 
New Fermat number divisor!  ET_  Factoring  1  20041008 03:34 