20200915, 15:50  #12 
Sep 2002
Database er0rr
3438_{10} Posts 
Code:
Mod(10,107)^100000000000000000000000000000000000000000 Mod(34, 107) ## *** last result computed in 0 ms It actually works by leftright binary exponentiation modulo n And since 107 is prime we can use Fermat's little theorem: Code:
Mod(10,107)^(100000000000000000000000000000000000000000%106) Mod(34, 107) Code:
Mod(10,107)^(100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%106) Mod(4, 107) Last fiddled with by paulunderwood on 20200915 at 16:06 
20200915, 16:06  #13  
"murat"
May 2020
turkey
53 Posts 
Quote:
Thanks 

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