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2005-03-17, 07:49
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#1 |
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Bronze Medalist
Jan 2004
Mumbai,India
22·33·19 Posts |
Kiddie problem.
 I am a 3 digit number. If you take away the 1st digit the remaining no. is 1/5th of the original 3 digit no. . If you take away the next digit the remaining no. is 1/5th of the 2 digit no. What no. am I?  Mally 
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2005-03-17, 12:16
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#2 |
May 2003
Belgium
2×139 Posts |
easy....
125 |
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2005-03-17, 17:02
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#3 | |
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Bronze Medalist
Jan 2004
Mumbai,India
22·33·19 Posts |
Kiddie problem
Quote:
Mally
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2005-03-18, 22:55
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#4 |
Jun 2003
1,579 Posts |
Here is the solution
125 Last fiddled with by Wacky on 2005-03-19 at 00:24 Reason: spoiler tag added |
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2005-03-23, 08:07
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#5 |
Sep 2002
748 Posts |
It's not really a 3 digit number... 000
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2005-03-24, 05:16
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#6 |
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3·11·79 Posts |
125
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2005-03-24, 16:09
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#7 | |
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Bronze Medalist
Jan 2004
Mumbai,India
22×33×19 Posts |
Kiddie problem
Quote:
 Was it guess work or you have a method? Mally
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2005-03-24, 19:57
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#8 |
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6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
2×33×173 Posts |
How about [b].[/b]125
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2005-03-24, 20:28
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#9 |
Sep 2002
Database er0rr
37×97 Posts |
And ""-12.5" assuming the that a half can be written as ".5""
(I don't think I have the blanking thingy sorted yet) |
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2005-03-24, 22:30
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#10 | |
"Sander"
Oct 2002
52.345322,5.52471
29·41 Posts |
Quote:
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2005-03-24, 22:41
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#11 |
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Sep 2002
Database er0rr
37·97 Posts |
Thanks
another the imaginary number -12.5i
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