20170515, 00:00  #1 
"Jonathan lafrance g"
May 2017
Maniwaki, quebec, ca
9_{10} Posts 
hypothese on some prime
I have an hypothese where for all number on 6n1 and on 11,17,23,29+30a, if its not factoring by any: (6a1) (6a+1) on where 6a1 is on 11,17,23,29+30c and 6a+1on 7,13,19,31+30bthen its prime. If it appears to be true would it be good to confirm a prime on 6n1 not on 5+30n, 25+30n

20170515, 02:36  #2  
"Forget I exist"
Jul 2009
Dumbassville
2^{4}·3·5^{2}·7 Posts 
Quote:
Last fiddled with by science_man_88 on 20170515 at 02:38 

20170515, 07:03  #3 
Romulan Interpreter
"name field"
Jun 2011
Thailand
2·5,059 Posts 
If the red question mark (which I added) is an ”or”, than your "hypothese" is true, and obvious. All primes, are by definition, "not factoring by" other primes (which are all either 6a1, either 6a+1).
If the red question mark is supposed to be a product, than your "hypothese" is false. There are composite numbers that have factors which are not a product of other 2 factors. They are called prime factors. Now, ok, if you multiply (1)(mod 6) and (1)(mod 6), you get either 5, 11, 17, 23, 29, (mod 30), and of course that any composite in these modular classes must be a multiple of that product. To reformulate: "I have a hypothese, any number which is not divisible by other number except 1 and itself, is prime". As you said, "cap and crap"... Last fiddled with by LaurV on 20170515 at 07:12 
20170515, 11:44  #4 
"Jonathan lafrance g"
May 2017
Maniwaki, quebec, ca
3^{2} Posts 
Well even if my education stopped right before complex number, thanks for call me a crap, lol, that is true I didnt define any limit where 6n1 and 6a1 share same equations when 6n1 * 6a1 >= 6b+1
6n1 >=7( 6a1 )and both on 11,17,23,29+30c 6n1>= 11(6b+1) where 6b+1 is on 7,13,19,31+ 30d My question is how long would it be for a computer to calculate all (6a1)(6b+1) until a certain 6n1 on 11,17,23,29,30+30c, where all my freaking variables are on naturals positives so from there soustration of the sums of all possible (6a1)(6b+1), between 6(n+1)1 and 6n+1 on the same freaking equations should be 0 for a prime and 1 on non prime. 
20170515, 12:44  #5  
"Forget I exist"
Jul 2009
Dumbassville
20D0_{16} Posts 
Quote:
a multiplication of two potentially different 6n1: (6k1)(6j1)=36kj6k6j+1 = 6(6kjkj)+1 a multiplication of two potentially different 6n+1: (6k+1)(6j+1)= 36kj+6k+6j+1 = 6(6kj+k+j)+1 or a multiplication of a 6n+1 by a 6n1: (6k+1)(6j1)=36kj6k+6j1 = 6(6kjk+j)1 assuming one of these values in the multiplication isn't 1 these are all composite. you can also use the fact that if prime r divides even one r will divide every r th one etc. Last fiddled with by science_man_88 on 20170515 at 13:14 

20170515, 16:01  #6 
"Jonathan lafrance g"
May 2017
Maniwaki, quebec, ca
3^{2} Posts 
So its possible that a number on 11, 17,23,29+ 30n that is not prime, could be factoring by other number than (11,17,23,29+30a)(7,13,19,31+30b), can iget an example? Where there are somes logicals limits. In my opinion there is no formula for prime but an absence of solution for all possible primes on ,7,11,13, 19,23,29, 31+30n, also i think prime is a relation to multiple of 6 but whatever, ill leave theses researchs to high end brain, cause I cant sleep since I started to work on it.

20170515, 16:11  #7  
Aug 2006
5,987 Posts 
Quote:
Is there an example of a composite number which is 11, 17, 23, or 29 mod 30 which is not of the form ab where a is 11, 17, 23, or 29 mod 30 and b is 1, 7, 13, or 19 mod 30? 

20170515, 19:50  #8 
"Jonathan lafrance g"
May 2017
Maniwaki, quebec, ca
3^{2} Posts 
For example, 161, is on 11+30n , and 6a1, his factors are 7 and 23 then, it,s like (6b+1)*(6c1) = 6n1 , is there any form of (6b+1)(6c+1) or (6b1)(6c1) = 6n1, excluding 5,25+30n demonstration on a forum but they say it,s weak because I have no knowledge for demonstration. But if my hypothese is true think i would be easy to determine if a number on 6a1 is prime.
If you know the number of false prime on 6n1 under n/7, then all possibilities: 11 *  7, 13, 19, 31, 37, until 11*a<= n/7 17 23 29 ... Until Closest number to n/7 then you want to test the closest number over last one, but the limits of n/7 will change and it can produce new factors , but since those 2 numbers are close, they share a lot of same factors under n/7, in my opinion if theyre is no new solution, than your number should beprime Also on a cycle of 30 they re 4 possibilities for 6n1, so its easy to determine how manysolutions you can get on a number Last fiddled with by Capncrap on 20170515 at 19:53 Reason: precision 
20170515, 20:54  #9  
"Forget I exist"
Jul 2009
Dumbassville
2^{4}·3·5^{2}·7 Posts 
Quote:


20170516, 17:21  #10 
"Jonathan lafrance g"
May 2017
Maniwaki, quebec, ca
3^{2} Posts 
I predicted 83 primes on (01000) on 11,17,23,29+30p
1000/11 >90,90 > 90 1000/7 > 142.85 > 142 So i know 90 is max on 7,13,19,31+30q And 142 max on 11,17,23,29+30r So: possible answer 1000/30 :33.333 but between 990 and 1000 there is nothing cause 11+30(33)=1001 Then 33 group of 4 possibilities : 132 So we can calculate non prime number 11 * 7, 13,19,31,37,43,49,61,67,73,79 > 11 possibilities 17* 7,13,19,31,37,43,49 > 7 possibilities 23* 7,13,19,31,37,43 > 6possibilities 29* 7, 13,19,31 > 4 possibilities 41*  7,13,19 > 3 47* 7,13,19 > 3 53* 7,13> 2 59*7,13 > 2 71* 7,13 > 2 77* 7 >1 83 * 7>1 89. > 1 101 >1 107>1 113 >1 119 > 1 131> 1 137>1 For a total of 49 possibilities 13249 = there are 83 primes on 6n1 between01000 
20170516, 17:32  #11 
"Jonathan lafrance g"
May 2017
Maniwaki, quebec, ca
3^{2} Posts 
Under my rule , 6p1=( 6q1)(6r+1)
6q1= 6s1 * 6t+1 you can keep going 6r+1 is 1 * 1 or +1*+1 >> (1*+1) * (1*+1) but always remind 6r+1 So my logic is if there at least one 6q1 or 6r+1 that divide 6p1 then its non prime 
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