2009-03-22, 03:39 | #1 |
2^{2}×3×523 Posts |
How To Find The Formula of This Permutations?
Hi to all of you guys here…
A friend of my husband gave him: 1). A paper with a table of 350 rows x 284 columns, which each cell contains of a single number from 0 to 9. This table didn’t typed yet into .xls file. It will be like table on sheet 5 of file Enigma-2.xls if it has. Since here I can’t attach .xls file, I put it at Mediafire.com (a file hosting service) name Enigma-2.xls: http://www.mediafire.com/?sharekey=0...4e75f6e8ebb871 2). A file name Enigma.xls like on sheet 1,2,3,4 of file Enigma-2.xls. He has remapped the table of 350 rows x 284 columns on that paper with: Column -> number of table (column 1->Table 1, column 2->Table 2, column 3->Table 3,...,column 284->Table 284). Cell Entries Index, 0 thru 9 in Column -> 10 Rows per new table (Rows 0,1,2,...9). Row -> Ascending list of cell entries where the row index exists in the original table whose column corresponds to this translated tables index. But he remapped the original table for 40 rows only. We were so lazy to type the original table manually to .xls file, so I want to convert it as I did on sheet 5 file Enigma-2.xls, but it didn’t work..? Can somebody help me about this? Now I’ve remapped it manually again per rows of that original table as on sheet 6 of file Enigma-2.xls with: Rows -> number of table (row 1->Table 1, row 2->Table 2, row 3->Table 3,...,row 40->Table 40). Cell Entries Index, 0 thru 9 in Row -> 10 Rows per new table (Rows 0,1,2,...9). Row -> Ascending list of cell entries where the column index exists in the original table whose row corresponds to this translated tables index Tables 1,5,9,13,17 / 41,45,49,53,57 / 21,25,29,33,37 / 61,65,69,73,77 on sheet 1 file Enigma-2. xls made us believe this infinite tables have some patterns of permutations that could be found to extend it for the next larger numbers 41,42,43,and so on, as I gave the blank tables on sheet 6 to be filled in… Hope my English is good enough for explaining this. Thx. |
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