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#1 |
Mar 2013
416 Posts |
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What will be the next (nearest) perfect square after 2^n (where n is a positive odd integer)? Can you suggest a formula or an algorithm for finding the next perfect square after 2^n?
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#2 |
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
9,257 Posts |
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It will be (isqrt(2n)+1)^2, where isqrt is easily calculated
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