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Old 2011-06-13, 14:44   #1
JohnFullspeed
 
May 2011
France

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Thumbs down Magic squaress

Sometimes you can write a value like the sum of two square
i/e 16+25= 51.... a= b²+c²
Are b and c unics?
John
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Old 2011-06-13, 14:53   #2
R.D. Silverman
 
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Quote:
Originally Posted by JohnFullspeed View Post
Sometimes you can write a value like the sum of two square
i/e 16+25= 51.... a= b²+c²
Are b and c unics?
John
What is a "unic"? I presume that you do not mean Eunuch.

It is a fairly simple elementary exercize to determine when a number
is the sum of two squares. It is an exercize for a 1st year number theory
class to determine when the representation is unique.

May I suggest that you perform some numerical experimentation to see
if you can hypothesize when the representation is unique.
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Old 2011-06-13, 14:58   #3
Mr. P-1
 
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Quote:
Originally Posted by JohnFullspeed View Post
Sometimes you can write a value like the sum of two square
i/e 16+25= 51.... a= b²+c²
Are b and c unics?
John
No. For example: 5²+10² = 11²+2²
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Old 2011-06-13, 15:03   #4
R.D. Silverman
 
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Quote:
Originally Posted by Mr. P-1 View Post
No. For example: 5²+10² = 11²+2²
Don't spoil it!!!!!!
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Old 2011-06-13, 15:24   #5
davieddy
 
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"Magic Squaress" sound's like the ideal title to bestow on
Alice Through the Looking Glass

Last fiddled with by davieddy on 2011-06-13 at 15:32
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Old 2011-06-13, 16:08   #6
Ralf Recker
 
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Quote:
Originally Posted by JohnFullspeed View Post
Sometimes you can write a value like the sum of two square
i/e 16+25= 51.... a= b²+c²
Are b and c unics?
John
51?

Last fiddled with by Ralf Recker on 2011-06-13 at 16:09
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Old 2011-06-13, 16:36   #7
science_man_88
 
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Quote:
Originally Posted by Ralf Recker View Post
51?
my guess is they either don't know math or that's a typo as 4 is next to 5 on the keyboard and the answer really is 41 in decimal.
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Old 2011-06-13, 18:01   #8
JohnFullspeed
 
May 2011
France

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Default Sorry

http://www.mersenneforum.org/showthread.php?t=15623

In fact i need to find 5 polynoms

a²+b²+c²+d².....i²+j² =Z
Is there a math mehod?
thanks

Last fiddled with by JohnFullspeed on 2011-06-13 at 18:16 Reason: typo errors
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Old 2011-06-13, 18:32   #9
R.D. Silverman
 
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Quote:
Originally Posted by JohnFullspeed View Post
http://www.mersenneforum.org/showthread.php?t=15623

In fact i need to find 5 polynoms

a²+b²+c²+d².....i²+j² =Z
Is there a math mehod?
thanks
As posted, this is gibberish. No problem is presented. No question
is asked. What are you looking for? 5 polynomials for what?
You have only defined an integer Z as the sum of 10 squares.

Last fiddled with by R.D. Silverman on 2011-06-13 at 18:36
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Old 2011-06-13, 19:05   #10
science_man_88
 
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Quote:
Originally Posted by R.D. Silverman View Post
As posted, this is gibberish. No problem is presented. No question
is asked. What are you looking for? 5 polynomials for what?
You have only defined an integer Z as the sum of 10 squares.
magic squares wouldn't ever have 10 squares either as they are n by n with a magic constant so I can't so far make any sense of it either.
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Old 2011-06-13, 19:06   #11
CRGreathouse
 
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Quote:
Originally Posted by R.D. Silverman View Post
You have only defined an integer Z as the sum of 10 squares.
...which doesn't even tell us anything about Z, since all nonnegative integers are the sum of 10 squares.
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