20180828, 13:27  #1 
Oct 2011
2^{2}·5·19 Posts 
Aliquot sequences that start on the integer powers n^i
On my website, I wrote a page that summarizes my work on aliquot sequences starting on integer powers n^i. This page summarizes the results and reservations for each aliquot sequences one has chosen to calculate.
See this page. If someone in this forum also wants to calculate these aliquot sequences with me, he can indicate it to me here and I note his name in the cells of my page to reserve him the integer powers of his choice. He will then have to enter the results into factordb and let me know so that I can fill and color the cells of the array as appropriate. Note : For openend aliquot sequences, I stop at 10^120 (orange color cells). 
20180829, 15:38  #2 
Romulan Interpreter
Jun 2011
Thailand
21660_{8} Posts 
I am (occasionally) working on 6^n, the progress for the larger seq is due to me, in the past.

20180830, 12:52  #3 
Oct 2011
2^{2}·5·19 Posts 
OK LaurV,
Do you remember for which i values you calculated the aliquot sequences of 6^i ? So I can add your name instead of "A" (Anonymous) in the array. 
20180830, 17:56  #4 
Romulan Interpreter
Jun 2011
Thailand
9136_{10} Posts 
Below 20 (and inclusive) the only sequences which do not terminate are 6^(7, 9, 11, 15, 19).
They are all at the point where I left them, except for few terms of 6^15 added by the elves where the last cofactor was under 110 digits. I work on 10077696 (6^9), and I reserved 95280 years ago, when 279936 (6^7) merged with it. I brought it to 148 digits (currently with a C140 cofactor, I still have it reserved, but not in priority list due to the 2^4*31 driver). Interesting that even powers (including higher, to 30 or 50, can't remember) all terminate, some in very large primes. Also, odd powers between 21 and 31 were left after C>100, and were advanced a bit by the DB elves. Last fiddled with by LaurV on 20180830 at 17:56 
20180830, 21:42  #5  
Oct 2011
2^{2}·5·19 Posts 
Quote:
Quote:
If n is odd and if and only if n takes the form n=m^2, then sigma(n)n will be even. See the proof, but sorry, in french. So, because n=6^i always is even, and n takes the form n=m^2 only when i is even, then, sigma(n)n will be odd and the aliquot sequence will go down. If i is odd, then we will probabily have an OpenEnd aliquot sequence. If for example, we take n=5^i which always is odd, when i is even then n takes the form n=m^2, so sigma(n)n will be even, so the aliquot sequence will probabily be OpenEnd. If for example, we take n=2^i which always takes the form m^2 (if i is even) or the form 2 * m^2 (if i is odd), then, sigma(n)n will always be odd, so the aliquot sequence will probabily always go down. I would like to find one i with 2^i an openend sequence, but I haven't found such an aliquot sequence yet. 

20180919, 19:40  #6 
Oct 2011
2^{2}·5·19 Posts 
Thanks to Karsten Bonath for completely redesigning my calculation tracking web page.
The new page is much more readable and allows immediate access to the data on FactorDB with a simple click. For the moment, only some aliquots sequences for n=2^i, 3^i, 6^i and 11^i are reserved. 
20180919, 23:22  #7 
Sep 2008
Kansas
41·79 Posts 
AS 11^56 terminates.
Edit: AS 11^58 terminates. Last fiddled with by RichD on 20180919 at 23:46 
20180920, 01:19  #8 
Sep 2008
Kansas
CA7_{16} Posts 
AS 10^108 terminates.
AS 10^104 terminates, not by me. 
20180921, 00:03  #9 
Sep 2002
Vienna, Austria
3×73 Posts 
6^77 terminates.

20180923, 20:26  #10 
Oct 2011
2^{2}×5×19 Posts 
OK,
RichD and wpolly, page updated. Thank you for your help ! 
20180925, 14:04  #11 
Sep 2008
Kansas
110010100111_{2} Posts 
10^106 terminates with a prime  91909.
Last fiddled with by RichD on 20180925 at 14:05 Reason: 10, not 11 
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