 mersenneforum.org Four Fours
 Register FAQ Search Today's Posts Mark Forums Read  2007-03-07, 03:28 #111 petrw1 1976 Toyota Corona years forever!   "Wayne" Nov 2006 Saskatchewan, Canada 10001101110012 Posts 171 = 172 = 44 * 4 - 4 173 = 174 = 44 * 4 - √4 Yes, I took the two easy ones ... I'm still trying the other two Last fiddled with by petrw1 on 2007-03-07 at 03:29   2007-03-08, 10:05   #112

"Richard B. Woods"
Aug 2002
Wisconsin USA

170148 Posts Quote:
 Originally Posted by petrw1 171 = 172 = 44 * 4 - 4 173 = 174 = 44 * 4 - √4 Yes, I took the two easy ones ... I'm still trying the other two
Back in post #10 of this thread, Wacky proposed an "interesting" rule we've followed since then:
Quote:
 Originally Posted by Wacky And just to keep it "interesting", no skipping around. :) You have to wait to post "7" until someone posts a solution for 6", etc. Posting "better" solutions for smaller numbers is fine.
So, we need 171 before proceeding further. :-)

Last fiddled with by cheesehead on 2007-03-08 at 10:08   2007-03-08, 18:03 #113 Andi47   Oct 2004 Austria 2·17·73 Posts I did not find anything without gamma... 171 = gamma(gamma(4)) / √.4~ - 4/.4~ 173 = gamma(gamma(4)) + (4! - .4~)/.4~ Edit: going further: 175 = ((4 + 4!) / .4) / .4 176 = 44 * (√4 + √4) Last fiddled with by Andi47 on 2007-03-08 at 18:05   2007-03-22, 01:30 #114 fetofs   Aug 2005 Brazil 2×181 Posts We move on after 177: 177 = ((√4 / .4)! - √4) / √.4~ 178 = (4 * 44) + √4 179 = ((4 + √4)! - 4) / 4 180 = 4 + (4 * 44) Last fiddled with by fetofs on 2007-03-22 at 01:41 Reason: using fancy sqrt symbol   2007-03-22, 01:38   #115
fetofs

Aug 2005
Brazil

2×181 Posts Some better solutions (note that I consider too many square roots to be ugly):

Quote:
 164 = √(√(√(4^4!)))) / .4 + 4 165 = (√4+ √(√(√(4^4!))))) / .4 170 = (√(√(√(4^4!))) + 4) / .4
164 = (√4 / .4)! + 44
165 = 44 / (.4 * √.4~)
170 = (4! + 44) / .4

Last fiddled with by fetofs on 2007-03-22 at 01:41   2007-03-22, 02:11 #116 PrimeCrazzy   Dec 2005 E16 Posts Suggestion I suggest you allow two additional functions, sum and subfacorial. S4 = 4+3+2+1= 10 (I do not have a sigma on my computer) !4= 9 These are sometimes accepable in this game.   2007-03-22, 05:51 #117 Andi47   Oct 2004 Austria 9B216 Posts 181 = ((√4 / .4)! + √.4~)/√.4~   2007-03-22, 13:03 #118 fetofs   Aug 2005 Brazil 36210 Posts 181 = (4 + (4 + sqrt(4))!) / 4 182 = ((4 + sqrt(4))! / 4) + sqrt(4) 183 = (sqrt(4) + (sqrt(4) / .4)!) / sqrt(.4~) 184 = 4 * (sqrt(4) + 44) Is 185 possible?   2007-03-22, 20:25   #119
petrw1
1976 Toyota Corona years forever!

"Wayne"
Nov 2006

11B916 Posts Quote:
 Originally Posted by fetofs Is 185 possible?
I didn't think 181 or 183 was possible ... but you proved me wrong.

So I won't try to guess if 185 is possible.   2007-03-22, 21:04   #120
Andi47

Oct 2004
Austria

2·17·73 Posts I did not find anything without gamma.

185 = gamma(gamma(4)) + √(√(√(4^4!))) + gamma(√4))

Quote:
 Originally Posted by PrimeCrazzy I suggest you allow two additional functions, sum and subfacorial. S4 = 4+3+2+1= 10 (I do not have a sigma on my computer) !4= 9 These are sometimes accepable in this game.
You can get the gamma function for positive integers quite easily:

gamma(n) = (n-1)!

examples:

gamma(√4) = 1! = 1
gamma(4) = 3! = 6
gamma(gamma(4)) = 5! = 120   2007-03-23, 02:51 #121 PrimeCrazzy   Dec 2005 1410 Posts You can also get 185 by using the sum and subfactorial functions ad follows: (sum(sum4))*sqrt (4 subfactorial)+sum4+sum4   Thread Tools Show Printable Version Email this Page

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