![]() |
![]() |
#1 |
Mar 2016
419 Posts |
![]()
A peaceful and pleasant night for you,
Let f(n)=2n²-1 n=a+bk then f(a+bk)=2(a+bk)²-1= 2(a²+2abk+b²k²)=2a²+4abk+2b²k²=g(k) if t|f(n) for which k t|g(k) ? I am today a little bit stupid and if someone could give me a hint, it would be nice. ![]() ![]() ![]() |
![]() |
![]() |
![]() |
#2 |
Mar 2016
41910 Posts |
![]()
Solving the linear substitution to k will do it.
![]() ![]() ![]() |
![]() |
![]() |
![]() |
#3 |
Mar 2016
419 Posts |
![]()
A friendly good night for you
Let f(n)=2n²-1 and t|f(no) g(k)=2k²-1 - C where C is a constant for which k0 t|g(ko) ? this is not a linear substitution and I will be glad knowing the answer. ![]() ![]() ![]() |
![]() |
![]() |
![]() |
Thread Tools | |
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
linear substitution and sieving | bhelmes | Number Theory Discussion Group | 10 | 2020-12-02 00:39 |