20150717, 15:31  #34  
"Victor de Hollander"
Aug 2011
the Netherlands
49B_{16} Posts 
Quote:


20150717, 16:14  #35 
1976 Toyota Corona years forever!
"Wayne"
Nov 2006
Saskatchewan, Canada
5^{2}×211 Posts 
Same person finds different factor via ECM and PM1 on the same day
Code:
Mn Status Details 131009 Factored 1937759097343 15368075063617012721 469572650565399789119183 251874321670721973902750994646081 History Date User Type Result 20150717 BloodIce FECM Factor: 469572650565399789119183 / (ECM curve 99, B1=250000, B2=25000000) 20150717 BloodIce FPM1 Factor: 251874321670721973902750994646081 / (P1, B1=50000000) 20090305 ANONYMOUS FECM Factor: 15368075063617012721 
20150717, 18:53  #36 
Dec 2012
3^{2}·31 Posts 

20150717, 21:46  #37 
Feb 2013
491_{10} Posts 
Hi, Jayder.
Try multiplying Mersenne 48 with the factor 3, next try factorizing the number you get. It should not be that difficult. If I happen to multiply a known RSA factor with a Fermat factor, I might end up at a number like this, 19036657588412969111505965532704495313206606970654378333477575250997660572 96146492268504477755829049148371391847449774943227537240957345732440163922533773 3449295565780737 It is a C170, by the way. Try factorizing this number. Based on the information given, it should not be an impossible thing to do. Edit: I only read page 3 here before posting. The last page for some reason slipped my fingers. Last fiddled with by storflyt32 on 20150717 at 21:51 
20150717, 21:57  #38 
Feb 2013
491 Posts 

20150718, 15:34  #39  
Sep 2009
100101111001_{2} Posts 
Quote:
Chris 

20150719, 12:02  #40 
Feb 2013
491 Posts 
Thanks!
Also while noticing the other one as well, I took the time of doing the same with the other P116 of RSA232. But perhaps this was not a result of factorization skills or ability, but rather something else instead. Last fiddled with by storflyt32 on 20150719 at 12:03 
20150725, 10:50  #41 
Dec 2002
2^{5}·3^{3} Posts 
Found a factor for exponent 12408313 through P1. Two factors actually. The pc used E=12 for the factoring and came up with a B2 limit for regular P1 just 10% under a billion. Nice found.

20150911, 02:08  #42 
Feb 2013
491 Posts 
(4331*2^1255628+1) has factors 3, 3 and 7 (63)
The remaining part is composite. pfgw64 q"((4331*2^1255628+1)/63)" PFGW Version 3.7.7.64BIT.20130722.Win_Dev [GWNUM 27.11] ((4331*2^1255628+1)/63) is composite: RES64: [05A11D83AA626AEE] (1756.0910s+0.0013s) Last fiddled with by storflyt32 on 20150911 at 02:33 
20150911, 05:00  #43 
Feb 2013
111101011_{2} Posts 
http://factordb.com/index.php?id=1100000000803014320
The initial C169 there. Added the P18 right now. The rest or remaining is still in the blue. Try "dividing" the C1133 of (2^4096+1) on this C169 and see what you get. I could add this factor as well. http://factordb.com/index.php?id=1100000000803014664 My best one in a little while. Last fiddled with by storflyt32 on 20150911 at 05:38 
20150912, 22:57  #44 
Feb 2013
491 Posts 
C156 = 1046549594684669247529542854996104560606610105651308122647323036788396252
83702968161057585901197429244373750447622645448631676673651879291916651670550446 647 http://factordb.com/index.php?id=1100000000226834094 "Divide" this number from RSA1024 above and and next factor it and you get a P152 back in return. http://factordb.com/index.php?id=1100000000803112399 Done already for orders sake. Last fiddled with by storflyt32 on 20150912 at 23:01 
Thread Tools  
Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Can Pollard Rho cycles be used to find a factor?  wwf  Factoring  26  20130930 04:24 
PFGW can't find a small factor.  Arkadiusz  Software  7  20130218 12:43 
Chance to find an ndigit factor with ECM  RedGolpe  Factoring  4  20070323 15:24 
How much ECM does it take to find a given factor?  geoff  Factoring  5  20040929 20:14 
Where I find the best program to it factor keys? I use AMD.  chrow  Factoring  5  20040219 10:15 