Poll: Which is the worst driver

Greebley · 2009-10-22, 14:55

I was curious what people thought was the worst driver. By this I mean the driver that you least like to see. Basically it is the one that the hardest one to escape before the sequence reaches numbers too high to continue.

Commonness can also enter into your choice; some drivers are hard to escape, but fairly rare so effect only a very few sequences.

TimSorbet · 2009-10-22, 16:19

I think 2^43112608*(2^43112609-1) would be the hardest known driver to escape from, but thankfully it's exceedingly rare for our purposes.

Greebley · 2009-10-22, 16:35

Ya, that's why I stated it as "worst" rather than "hardest to escape".

Note though that once you get a square on the big term, the chances of having a power of two high enough is very small, so multiples of large perfect numbers will tend to escape the first time they get a square unless the value is truly huge (big enough to have billions of factors on average)

henryzz · 2009-10-22, 17:40

2^2*7 is the one that annoys me most
i would guess that 2^6 * 127 is the hardest listed driver to escape

BigBrother · 2009-10-22, 17:49

Quote:

Originally Posted by henryzz

2^2*7 is the one that annoys me most
i would guess that 2^6 * 127 is the hardest listed driver to escape

2^2*7 is my nemesis too. And I always hate it when a 5 shows up!

henryzz · 2009-10-22, 17:52

Quote:

Originally Posted by BigBrother

2^2*7 is my nemesis too. And I always hate it when a 5 shows up!

if it comes to hating a particular factor i would say definitely 3

unconnected · 2009-10-22, 18:06

I hate 2*3 driver. Never met 2^9*3*11*31

henryzz · 2009-10-22, 18:25

Quote:

Originally Posted by unconnected

I hate 2*3 driver. Never met 2^9*3*11*31

2*3 is possibly the easiest perfect number driver to lose i think

10metreh · 2009-10-24, 07:45

I voted 2^4 * 31 because I've never encountered 2^6 * 127 myself, but I have encountered 2^4 * 31 a lot. (And I've only ever escaped it once.)

View Poll Results: Which driver is the worst for termination?
2*3	1	6.67%
2^2*7	5	33.33%
2^335	6	40.00%
2^4*31	1	6.67%
2^537	0	0%
2^6*127	1	6.67%
2^9311*31	0	0%
Other	1	6.67%
Voters: 15. You may not vote on this poll

2009-10-22, 14:55	#1
Greebley May 2009 Dedham Massachusetts USA 1513₈ Posts	Poll: Which is the worst driver I was curious what people thought was the worst driver. By this I mean the driver that you least like to see. Basically it is the one that the hardest one to escape before the sequence reaches numbers too high to continue. Commonness can also enter into your choice; some drivers are hard to escape, but fairly rare so effect only a very few sequences.

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2009-10-22, 16:19	#2
TimSorbet Account Deleted "Tim Sorbera" Aug 2006 San Antonio, TX USA 10B7₁₆ Posts	I think 2^43112608*(2^43112609-1) would be the hardest known driver to escape from, but thankfully it's exceedingly rare for our purposes.

2009-10-22, 16:35	#3
Greebley May 2009 Dedham Massachusetts USA 3×281 Posts	Ya, that's why I stated it as "worst" rather than "hardest to escape". Note though that once you get a square on the big term, the chances of having a power of two high enough is very small, so multiples of large perfect numbers will tend to escape the first time they get a square unless the value is truly huge (big enough to have billions of factors on average)

2009-10-22, 17:40	#4
henryzz Just call me Henry "David" Sep 2007 Liverpool (GMT/BST) 13620₈ Posts	2^27 is the one that annoys me most i would guess that 2^6 127 is the hardest listed driver to escape

2009-10-22, 18:06	#7
unconnected May 2009 Moscow, Russia 3·5·193 Posts	I hate 23 driver. Never met 2^931131

2009-10-24, 07:45	#9
10metreh Nov 2008 2·3³·43 Posts	I voted 2^4 * 31 because I've never encountered 2^6 * 127 myself, but I have encountered 2^4 * 31 a lot. (And I've only ever escaped it once.)