mersenneforum.org Impossible Integral
 User Name Remember Me? Password
 Register FAQ Search Today's Posts Mark Forums Read

 2008-03-06, 03:10 #1 Unregistered   811410 Posts Impossible Integral Alright, so this is a Calculus 2 homework problem and my friends and I are completely stuck. The original question is to find if the Summat of {tan^-1 (x)}/x^1.1 (from 1 to infinity)converges or diverges, and if it converges to find its sum. Using the Integral Test, we said that this series, did in fact converge. The problem was in evaluating the integral. Integral (1 to infinity) of (tan^-1 (x))/x^1.1 We cannot manage to evaluate this... no theorem or rule we can find helps in this evaluation. Any help would be greatly appreciated. Thanks!
2008-03-06, 15:46   #2
R.D. Silverman

"Bob Silverman"
Nov 2003
North of Boston

750810 Posts

Quote:
 Originally Posted by Unregistered Alright, so this is a Calculus 2 homework problem and my friends and I are completely stuck. The original question is to find if the Summat of {tan^-1 (x)}/x^1.1 (from 1 to infinity)converges or diverges, and if it converges to find its sum. Using the Integral Test, we said that this series, did in fact converge. The problem was in evaluating the integral. Integral (1 to infinity) of (tan^-1 (x))/x^1.1 We cannot manage to evaluate this... no theorem or rule we can find helps in this evaluation. Any help would be greatly appreciated. Thanks!
(1) Using the integral test is hitting a fly with a hammer. Instead,
simply note that the numerator is bounded above by pi, and that sum(pi/x^1.1)) clearly converges.

(2) Evaluating the integral that you gave will not give the sum of the series.
For that, you need Euler-MacLauren summation.

(3) The indefinite integral can probably be expressed in terms of hyper-
geometric functions. It is very unlikely that a closed form expression exists
for the sum.

(4) To evaluate your infinite integral, I would use complex contour integration
methods, along with Cauchy's Theorem. Start by finding the residues of the
series; this requires a Laurent expansion. I won't even attempt it by hand.
I would want to use Mathematica. I would use a quarter-circle contour centered at 0.

The integral can't be expressed in terms of elementary functions.
Finding the sum seems well beyond a 2nd year calculus course.

 2008-03-06, 21:16 #3 Unregistered   22·17·131 Posts The original problem was to find if SIGMA [(tan^-1 (n)/n^1.1)] from 1 to infinity converges and if it converges to find its sum. I proved that it converges using the Integral test. Using 2nd year calculus tools, how would you find the sum? A 3rd year calc student mentioned something about a comparison that could be done involving pi/2.
2008-03-07, 12:30   #4
R.D. Silverman

"Bob Silverman"
Nov 2003
North of Boston

22·1,877 Posts

Quote:
 Originally Posted by Unregistered The original problem was to find if SIGMA [(tan^-1 (n)/n^1.1)] from 1 to infinity converges and if it converges to find its sum. I proved that it converges using the Integral test. Using 2nd year calculus tools, how would you find the sum?
You don't. I doubt very much whether the sum has a closed form.
It *might* be expressible in terms of hypergeometric functions.
Why do I think this? Because integral ATAN(x)/x dx has such a
representation.

 2008-03-07, 12:42 #5 R. Gerbicz     "Robert Gerbicz" Oct 2005 Hungary 161110 Posts By Mathematica 5.1 the integral is (see the attachment) Attached Thumbnails
 2008-03-08, 20:05 #6 m_f_h     Feb 2007 1B016 Posts since convergence is indeed ensured by comparision with (pi/2)/x^1.1, why not do it numerically... gp> intnum(x=1,[1],atan(x)/x^1.1) %1 = 14.879905283440983234832458288559145866892862726910 gp> ## *** last result computed in 140 ms. But here's a primitive from Maple: -10/x^(1/10)*arctan(x) +5/2*sqrt(2)*ln((x^(1/5)+x^(1/10)*sqrt(2)+1)/(x^(1/5)-x^(1/10)*sqrt(2)+1)) +5*sqrt(2)*arctan(x^(1/10)*sqrt(2)+1) +5*sqrt(2)*arctan(x^(1/10)*sqrt(2)-1) -20*sum(_R*ln(x^(1/10)-262144*_R^9),_R = RootOf(4294967296*_Z^16-16777216*_Z^12+65536*_Z^8-256*_Z^4+1)) Taking the limit x=infinity seems obvious except for the last term. (might have changed 4Z into Z'...)

 Thread Tools

 Similar Threads Thread Thread Starter Forum Replies Last Post wildrabbitt Homework Help 2 2016-04-08 08:21 Unregistered Information & Answers 6 2013-06-14 12:38 Baztardo Homework Help 6 2011-04-10 22:17 flouran Information & Answers 6 2009-07-20 20:00 Andi47 Homework Help 3 2009-05-13 17:49

All times are UTC. The time now is 22:31.

Wed Feb 1 22:31:14 UTC 2023 up 167 days, 19:59, 0 users, load averages: 2.10, 1.28, 1.15

Powered by vBulletin® Version 3.8.11
Copyright ©2000 - 2023, Jelsoft Enterprises Ltd.

This forum has received and complied with 0 (zero) government requests for information.

Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation License, Version 1.2 or any later version published by the Free Software Foundation.
A copy of the license is included in the FAQ.

≠ ± ∓ ÷ × · − √ ‰ ⊗ ⊕ ⊖ ⊘ ⊙ ≤ ≥ ≦ ≧ ≨ ≩ ≺ ≻ ≼ ≽ ⊏ ⊐ ⊑ ⊒ ² ³ °
∠ ∟ ° ≅ ~ ‖ ⟂ ⫛
≡ ≜ ≈ ∝ ∞ ≪ ≫ ⌊⌋ ⌈⌉ ∘ ∏ ∐ ∑ ∧ ∨ ∩ ∪ ⨀ ⊕ ⊗ 𝖕 𝖖 𝖗 ⊲ ⊳
∅ ∖ ∁ ↦ ↣ ∩ ∪ ⊆ ⊂ ⊄ ⊊ ⊇ ⊃ ⊅ ⊋ ⊖ ∈ ∉ ∋ ∌ ℕ ℤ ℚ ℝ ℂ ℵ ℶ ℷ ℸ 𝓟
¬ ∨ ∧ ⊕ → ← ⇒ ⇐ ⇔ ∀ ∃ ∄ ∴ ∵ ⊤ ⊥ ⊢ ⊨ ⫤ ⊣ … ⋯ ⋮ ⋰ ⋱
∫ ∬ ∭ ∮ ∯ ∰ ∇ ∆ δ ∂ ℱ ℒ ℓ
𝛢𝛼 𝛣𝛽 𝛤𝛾 𝛥𝛿 𝛦𝜀𝜖 𝛧𝜁 𝛨𝜂 𝛩𝜃𝜗 𝛪𝜄 𝛫𝜅 𝛬𝜆 𝛭𝜇 𝛮𝜈 𝛯𝜉 𝛰𝜊 𝛱𝜋 𝛲𝜌 𝛴𝜎𝜍 𝛵𝜏 𝛶𝜐 𝛷𝜙𝜑 𝛸𝜒 𝛹𝜓 𝛺𝜔