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#1 |
Mar 2018
72×11 Posts |
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a(9)=36
a(18)=1323 a(27)=69660 a(36)=360787 pg(36), pg(1323) and pg(69660) and pg(360787) are primes a(9) is the 9-th exponent leading to a ec prime a(18) the 18-th a(27) the 27-th a(36) the 36-th 36,1323,69660 and 360787 are divisible by a perfect square 36 and 69660 (even) are divisible by a square which is a 3 smooth number (infact 36 is divisible by 36 which is 3 smooth, 69660 is divisible by 18^2 whcih is 3 smooth) 1323 and 360787 (odd) are divisible by 21^2 and by 7^2 which are squares that are 7-smooth numbers so 36,1323,69660, 360787 are divisible either by 3^2*6^2 or by 3^2*7^2 or by 6^2 or by 7^2 360787 (mod (14^3)) is 1323 36 and 69660 even are of the form 8k+4 1323 and 360787 (odd) are of the form 8k+3 Last fiddled with by enzocreti on 2020-08-27 at 09:48 |
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