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 2005-03-17, 07:49 #1 mfgoode Bronze Medalist     Jan 2004 Mumbai,India 22×33×19 Posts Kiddie problem. I am a 3 digit number. If you take away the 1st digit the remaining no. is 1/5th of the original 3 digit no. . If you take away the next digit the remaining no. is 1/5th of the 2 digit no. What no. am I? Mally
 2005-03-17, 12:16 #2 sonjohan     May 2003 Belgium 2×139 Posts easy.... 125
2005-03-17, 17:02   #3
mfgoode
Bronze Medalist

Jan 2004
Mumbai,India

205210 Posts
Kiddie problem

Quote:
 Originally Posted by sonjohan easy.... 125
Simple, wasn't it?

Mally

 2005-03-18, 22:55 #4 Citrix     Jun 2003 32×52×7 Posts Here is the solution 125 Last fiddled with by Wacky on 2005-03-19 at 00:24 Reason: spoiler tag added
 2005-03-23, 08:07 #5 asdf     Sep 2002 3C16 Posts It's not really a 3 digit number... 000
 2005-03-24, 05:16 #6 Pr|med   25×3×101 Posts 125
2005-03-24, 16:09   #7
mfgoode
Bronze Medalist

Jan 2004
Mumbai,India

22·33·19 Posts
Kiddie problem

Quote:
 Originally Posted by Pr|med 125

Was it guess work or you have a method?
Mally

 2005-03-24, 19:57 #8 Uncwilly 6809 > 6502     """"""""""""""""""" Aug 2003 101×103 Posts 3·13·229 Posts How about [b].[/b]125
 2005-03-24, 20:28 #9 paulunderwood     Sep 2002 Database er0rr 5·701 Posts And ""-12.5" assuming the that a half can be written as ".5"" (I don't think I have the blanking thingy sorted yet)
2005-03-24, 22:30   #10
smh

"Sander"
Oct 2002
52.345322,5.52471

29×41 Posts

Quote:
 (I don't think I have the blanking thingy sorted yet)
See the sticky post in this forum

 2005-03-24, 22:41 #11 paulunderwood     Sep 2002 Database er0rr 66618 Posts Thanks another the imaginary number -12.5i

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