Four Fours - Page 11

petrw1 · 2007-03-07, 03:28

171 =
172 = 44 * 4 - 4
173 =
174 = 44 * 4 - √4

Yes, I took the two easy ones ... I'm still trying the other two

cheesehead · 2007-03-08, 10:05

Quote:

Originally Posted by petrw1

171 =
172 = 44 * 4 - 4
173 =
174 = 44 * 4 - √4

Yes, I took the two easy ones ... I'm still trying the other two

Back in post #10 of this thread, Wacky proposed an "interesting" rule we've followed since then:

Quote:

Originally Posted by Wacky

And just to keep it "interesting", no skipping around. :)
You have to wait to post "7" until someone posts a solution for 6", etc.
Posting "better" solutions for smaller numbers is fine.

So, we need 171 before proceeding further. :-)

Andi47 · 2007-03-08, 18:03

I did not find anything without gamma...

171 = gamma(gamma(4)) / √.4~ - 4/.4~

173 = gamma(gamma(4)) + (4! - .4~)/.4~

Edit: going further:

175 = ((4 + 4!) / .4) / .4
176 = 44 * (√4 + √4)

fetofs · 2007-03-22, 01:30

We move on after 177:

177 = ((√4 / .4)! - √4) / √.4~
178 = (4 * 44) + √4
179 = ((4 + √4)! - 4) / 4
180 = 4 + (4 * 44)

fetofs · 2007-03-22, 01:38

Some better solutions (note that I consider too many square roots to be ugly):

Quote:

164 = √(√(√(4^4!)))) / .4 + 4
165 = (√4+ √(√(√(4^4!))))) / .4
170 = (√(√(√(4^4!))) + 4) / .4

164 = (√4 / .4)! + 44
165 = 44 / (.4 * √.4~)
170 = (4! + 44) / .4

PrimeCrazzy · 2007-03-22, 02:11

I suggest you allow two additional functions, sum and subfacorial.

S4 = 4+3+2+1= 10 (I do not have a sigma on my computer)
!4= 9

These are sometimes accepable in this game.

Andi47 · 2007-03-22, 05:51

181 = ((√4 / .4)! + √.4~)/√.4~

fetofs · 2007-03-22, 13:03

181 = (4 + (4 + sqrt(4))!) / 4
182 = ((4 + sqrt(4))! / 4) + sqrt(4)
183 = (sqrt(4) + (sqrt(4) / .4)!) / sqrt(.4~)
184 = 4 * (sqrt(4) + 44)

Is 185 possible?

petrw1 · 2007-03-22, 20:25

Quote:

Originally Posted by fetofs

Is 185 possible?

I didn't think 181 or 183 was possible ... but you proved me wrong.

So I won't try to guess if 185 is possible.

Andi47 · 2007-03-22, 21:04

I did not find anything without gamma.

185 = gamma(gamma(4)) + √(√(√(4^4!))) + gamma(√4))

Quote:

Originally Posted by PrimeCrazzy

I suggest you allow two additional functions, sum and subfacorial.

S4 = 4+3+2+1= 10 (I do not have a sigma on my computer)
!4= 9

These are sometimes accepable in this game.

You can get the gamma function for positive integers quite easily:

gamma(n) = (n-1)!

examples:

gamma(√4) = 1! = 1
gamma(4) = 3! = 6
gamma(gamma(4)) = 5! = 120

PrimeCrazzy · 2007-03-23, 02:51

You can also get 185 by using the sum and subfactorial functions ad follows:

(sum(sum4))*sqrt (4 subfactorial)+sum4+sum4

2007-03-07, 03:28	#111
petrw1 1976 Toyota Corona years forever! "Wayne" Nov 2006 Saskatchewan, Canada 10712₈ Posts	171 = 172 = 44 * 4 - 4 173 = 174 = 44 * 4 - √4 Yes, I took the two easy ones ... I'm still trying the other two Last fiddled with by petrw1 on 2007-03-07 at 03:29

2007-03-08, 18:03	#113
Andi47 Oct 2004 Austria 2482₁₀ Posts	I did not find anything without gamma... 171 = gamma(gamma(4)) / √.4~ - 4/.4~ 173 = gamma(gamma(4)) + (4! - .4~)/.4~ Edit: going further: 175 = ((4 + 4!) / .4) / .4 176 = 44 * (√4 + √4) Last fiddled with by Andi47 on 2007-03-08 at 18:05

2007-03-22, 01:30	#114
fetofs Aug 2005 Brazil 2×181 Posts	We move on after 177: 177 = ((√4 / .4)! - √4) / √.4~ 178 = (4 * 44) + √4 179 = ((4 + √4)! - 4) / 4 180 = 4 + (4 * 44) Last fiddled with by fetofs on 2007-03-22 at 01:41 Reason: using fancy sqrt symbol

2007-03-22, 02:11	#116
PrimeCrazzy Dec 2005 2×7 Posts	Suggestion I suggest you allow two additional functions, sum and subfacorial. S4 = 4+3+2+1= 10 (I do not have a sigma on my computer) !4= 9 These are sometimes accepable in this game.

2007-03-22, 05:51	#117
Andi47 Oct 2004 Austria 2482₁₀ Posts	181 = ((√4 / .4)! + √.4~)/√.4~

2007-03-22, 13:03	#118
fetofs Aug 2005 Brazil 362₁₀ Posts	181 = (4 + (4 + sqrt(4))!) / 4 182 = ((4 + sqrt(4))! / 4) + sqrt(4) 183 = (sqrt(4) + (sqrt(4) / .4)!) / sqrt(.4~) 184 = 4 * (sqrt(4) + 44) Is 185 possible?

2007-03-23, 02:51	#121
PrimeCrazzy Dec 2005 E₁₆ Posts	You can also get 185 by using the sum and subfactorial functions ad follows: (sum(sum4))*sqrt (4 subfactorial)+sum4+sum4