20050111, 22:04  #1 
Jan 2005
13 Posts 
Hard proplem for finding sine function
hi everyone
here is the question: Find the sine function which satify these things below: For t =< 0, f(t) = 0 For 0< t < 1/2, f(t) follows a sine curve with a period of T = 1 sec and peak distance = 1 m For t >= 1/2, f(t)= 0 anyidea ? thanks everyone 
20050112, 01:31  #2 
Nov 2004
Florianopolis  Brazil
3×5 Posts 
I think you could use DFT or FFT.

20050112, 02:16  #3 
Jan 2005
13 Posts 
sorry, i dont know what is DFT or FFT.

20050112, 02:25  #4 
Nov 2004
Florianopolis  Brazil
3·5 Posts 
Discrete Fourier Transform
Fast Fourier Transform 
20050112, 02:45  #5  
Jan 2005
13 Posts 
Quote:
sin(pi*t) ; 0< t <.5 is that correct ? it doesn't seem right 

20050114, 20:23  #6  
∂^{2}ω=0
Sep 2002
República de California
26740_{8} Posts 
Quote:
For t =< 0, f(t) = 0 For 0< t < 1/2, f(t) = sin(2*pi*t) For t >= 1/2, f(t)= 0 Just plot sin(2*pi*t) between t = 0 and t = 0.5 on your graphing calculator and you'll see it hits zero at either end of the interval. Last fiddled with by ewmayer on 20050117 at 16:37 

20050117, 05:42  #7 
Jan 2005
15_{8} Posts 
thank you very much

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