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#1 |
"Jason Goatcher"
Mar 2005
350710 Posts |
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I have no idea how to even begin to solve this, I just want to see what strategies people use. :)
It is imperative that you break into a facility that's protected by keycards. You need access to all the sections.(I'm not going to say how many sections there are, we'll make that an open variable to study) You have one computer and a card attached to it, so you can come up with any passcode combination. Each time you attempt a combination that's wrong you're locked out for one minute. The passcode is 64 bits, meaning 2^64 combinations, but there's a bug in the software. Each time you attempt a guess, you find out if the number of bits that are correct is odd or even(you impersonate a specific employee with the card, so the passcode is the same for individual sections). For each section, you have to guess a new 64-bit passcode. Also, there is a master passcode, but it's 512 bits. After we figure out the approximate time for the 64-bit passcode, we want to know how many sections in the facility there would have to be for it to be a good idea to go straight for the 512-bit passcode. For the sake of the puzzle, the guards are all looking at porn on the Internet and will never notice you're there. ;) |
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#2 | |
Jun 2003
4,919 Posts |
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#3 |
"Jason Goatcher"
Mar 2005
3·7·167 Posts |
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For those of you who read axn's answer, I don't believe he's correct in saying it's impossible to solve. I have a germ of an answer, but I want to see what other say.
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#4 | |
Jun 2003
30538 Posts |
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Due to this bug it will take you 64 steps to crack the 64 bit code for each section. I don't understand the 512 bit thing. Last fiddled with by Citrix on 2007-11-23 at 23:28 |
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#5 |
"Jason Goatcher"
Mar 2005
350710 Posts |
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#6 |
Aug 2003
Snicker, AL
7×137 Posts |
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31 minutes to crack each of the 64 bit codes. There might be a way to optimize it still further, but 31 was the best I could get.
Following this through, you could crack the 512 bit code in 255 minutes. That means the master code should be attempted if there are 8 or more sections to the area. And no I won't post how I came up with 31 tries. But it is really simple. DarJones |
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#7 | |
Jun 2003
The Texas Hill Country
32×112 Posts |
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But I agree with axn1. It isn't that easy. After the first test reveals 1 bit of information, each of the rest can add only about 2^(-63) additional bits to the information. Now, if the test were to reveal something about the number of 1's without caring about any of the 0's, that would be a different situation. However, as the problem is stated, after the first test, I can completely predict the outcome of any other test, if it fails. Last fiddled with by Wacky on 2007-11-24 at 10:50 |
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