20190321, 13:21  #210 
Romulan Interpreter
"name field"
Jun 2011
Thailand
2^{4}×613 Posts 
My computer can do it in a quarter of that time. In fact, it can do it in a tenth of that time. In fact, it can do it in an infinitesmall fraction of that time.

20190321, 13:58  #211 
Sep 2002
Database er0rr
7537_{8} Posts 
Code:
? floor((31.4*10^12/10^4)^4) 97211712160000000000000000000000000000 Last fiddled with by paulunderwood on 20190321 at 14:08 
20190321, 15:03  #212  
May 2004
New York City
5×7×11^{2} Posts 
Quote:
(Although an "infinitesmall fraction" of an infinite time span might be infinite or finite itself.) 

20190321, 16:33  #213 
"Dana Jacobsen"
Feb 2011
Bangkok, TH
1615_{8} Posts 
Using GMP, assuming it all fits in memory and GMP scales fine, it's only 1.8 billion years to finish BPSW.
My single threaded Primo calculation came out to only exp( 4.01 * (log(3140000000000)log(2000)) + log(2313.8) ) / 60 / 60 / 24 / 365.25 = 550528055283376774128261550300497 years. Based on timings from a few years ago to compute various sizes up to 2000 digits, and assuming of course that we can just handwave practicality and scaling. AKS using Bernstein Theorem 4.1, about 5e59 years. But parallelism is trivial, so that will really help a lot. 
20200218, 21:05  #214 
"Mark"
Apr 2003
Between here and the
2·5·647 Posts 

20200815, 19:31  #215 
May 2004
New York City
5·7·11^{2} Posts 
What is the status of a(20)? Will it reach 10^6 soon?

20200815, 22:55  #216 
"Mark"
Apr 2003
Between here and the
14506_{8} Posts 

20201226, 01:54  #217 
May 2004
New York City
4235_{10} Posts 
Oh I see. I thought of a different possibility.

20210718, 18:03  #218 
May 2004
New York City
5·7·11^{2} Posts 
I want to apologize to all for some of my blatant goofs and attitudes in the past. Some egregious claims,
a wanting defense of the cosmology, even unclarity in this thread. This apology should yield some improvement from me. 
20210821, 12:19  #219 
Romulan Interpreter
"name field"
Jun 2011
Thailand
2^{4}×613 Posts 
I have heard that now we have enough digits to solve a(20). Any takers?
(or, how RDS would say, "have at it!" ) Last fiddled with by LaurV on 20210821 at 12:21 
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