20060116, 11:31  #133 
Aug 2002
Buenos Aires, Argentina
2^{2}×3×5×23 Posts 
I completed the 15digit level for M(30,402,457)2 and Prime95 only found the product of the three prime factors shown above.

20060126, 18:49  #134 
Aug 2002
Buenos Aires, Argentina
2^{2}×3×5×23 Posts 
Up to now: 8108 curves with B1 = 11000000 for 2^4253  3.

20060315, 13:40  #135 
Aug 2002
Buenos Aires, Argentina
2^{2}×3×5×23 Posts 
On March 1st, the computer finished the 10600th curve for 2^4253  3, so the 45digit level is completed for this number. There was no factor found.

20060911, 21:53  #136 
Jul 2003
Thuringia; Germany
2·29 Posts 
2^32582657 3 is divisible by 23 and 523657 (and no other prime < 5000000)
Cyrix 
20060920, 05:16  #137 
Einyen
Dec 2003
Denmark
3172_{10} Posts 
5918466629 is also a factor. No other factors below .
Last fiddled with by ATH on 20060920 at 05:17 
20081008, 06:56  #138 
May 2008
10001000111_{2} Posts 
2^431126093 has a factor: 191

20081008, 07:15  #139 
May 2008
3·5·73 Posts 
And
2^371566673 has factors:
5 859 549001 
20081008, 18:07  #140 
May 2008
3·5·73 Posts 

20081009, 00:42  #141 
Aug 2006
3×1,993 Posts 
another factor
2^371566673 = 5^2 * 859 * 549001 * 2201107 * ...
(and that's just 17 seconds of Pari/GP!) Last fiddled with by CRGreathouse on 20081009 at 00:55 
20100430, 16:40  #142  
Jan 2010
379 Posts 
Quote:
First, there cannot be such primes (3 primes with gap 2 between them). Secondly, a merssene number and a number of the form (2^n+1) cannot be twin primes. 

20100430, 17:26  #143 
Mar 2006
Germany
37·79 Posts 

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