20090816, 21:24  #1 
"Forget I exist"
Jul 2009
Dumbassville
10000011010000_{2} Posts 
Challenge
if you look at wikipedia the double mersenne primes go:
7, 127, 2147483647, 170141183460469231731687303715884105727 first all of them end in 7 next if you look at the table for mersenne primes they have: p Mp 3 7 7 127 127 170141183…884105727 If I'm right in assuming the last Mp is the last in this series and this pattern continues( the pattern is Mp becomes the next p) then the next one in this sub series( or what ever you want to call it) is: p 170141183460469231731687303715884105727 Mp 2^170,141,183,460,469,231,731,687,303,715,884,105, 7271 if this is true it smashes all records as the biggest prime to date and biggest mersenne prime is 2^46 million and something this is 2^ 170 Undecillion and something. I left gimps as it took to much time for me. but can anyone confirm this pattern or try it out if so it would be the biggest known prime. 
20090816, 21:26  #2 
"Forget I exist"
Jul 2009
Dumbassville
2^{4}×3×5^{2}×7 Posts 
Oh by the way it might take 21 tera tera tera bytes to write in binary form but anyone willing to try ?

20090816, 21:34  #3 
"Forget I exist"
Jul 2009
Dumbassville
20320_{8} Posts 
oh if you look at it the pattern would be
(2^3)1,(2^7)1,(2^2^7)1,(2^2^2^7)1,(2^2^2^2^7)1,.......................................................................................................... 
20090816, 21:38  #4 
Jul 2006
Calgary
5^{2}·17 Posts 
No one knows if the 3rd exponent yields a prime let alone the 4th. This is just someone's wild speculation.

20090816, 21:45  #5 
"Forget I exist"
Jul 2009
Dumbassville
2^{4}·3·5^{2}·7 Posts 
actually it's a pattern I saw as a possibility in the table but if you don't want to find out if M170,141,183,460,469,231,731,687,303,715,884,105,727 is prime
Last fiddled with by science_man_88 on 20090816 at 21:45 
20090816, 21:52  #6 
"Forget I exist"
Jul 2009
Dumbassville
2^{4}×3×5^{2}×7 Posts 
2^3 = 81 = 7
2^7 = 1281=127 2^127(messed up before) = 1701411834604692317316873037158841057281=170141183460469231731687303715884105727 2^1701411834604692317316873037158841057271 ? Last fiddled with by science_man_88 on 20090816 at 21:56 
20090816, 21:58  #7 
Jan 2009
Ireland
2×3×31 Posts 
it is impossible to confirm with todays technology.the only thing that can be done is confirm it is not prime.this can be done by trial factoring it with a program such as factor 5.it has already been trial factored up to around 170 bits without a factor.

20090816, 22:01  #8  
Jul 2006
Calgary
5^{2}·17 Posts 
Quote:
The record is 2^43112609  1 that was discovered last year by the GIMPS projects. 

20090816, 22:04  #9 
Jul 2006
Calgary
5^{2}×17 Posts 
I think it is too large for factor5 too. I suppose it could be tested for factors with some relatively simple new software but it doesn't realy seem worth the effort at this time.

20090816, 22:10  #10 
Jan 2009
Ireland
186_{10} Posts 
M170141183460469231731687303715884105727,MM127 can be tested with factor5.he also mentions MM31,i thought there was a factor found for it?

20090816, 22:18  #11 
Dec 2008
1501_{8} Posts 
Does science_man_88 = ? I am not sure yet, as I have not had much experience with the and related creatures.
Anyone agree/beg to differ? If so, I vote that this thread should be moved to Miscellaneous Math. Last fiddled with by flouran on 20090816 at 22:24 
Thread Tools  
Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
A Challenge on the net  devarajkandadai  Miscellaneous Math  0  20120531 05:17 
When I was your age.....CHALLENGE  petrw1  Lounge  14  20091123 02:18 
rsa640 challenge  ValerieVonck  Factoring  58  20051024 15:54 
Another challenge  R.D. Silverman  Programming  24  20050727 21:08 
Who is Challenge?  JuanTutors  PrimeNet  2  20040722 12:56 