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#1 |
Sep 2002
Database er0rr
DCC16 Posts |
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With the EFF award in mind, I am running this program:
Code:
forprime(q=1,100000000000,s=Mod(1416317954,q);for(k=7,33,s=s^2-2;if(s==2,print([q,k-2]);break))) [2, 5] [3, 5] [7, 5] [31, 5] [97, 5] [127, 7] [607, 5] [8191, 13] [12289, 10] [22783, 8] [131071, 17] [265471, 8] [524287, 19] [592897, 8] [1310719, 18] [21757951, 18] [29687809, 14] [39845887, 21] [665972737, 10] [708158977, 6] [2147483647, 31] [2210398207, 22] [2543310079, 8] [58133053441, 23] [60651732991, 21] ![]() (Note that 97 is there because k starts at 7.) Last fiddled with by paulunderwood on 2019-06-23 at 22:09 |
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#2 |
Sep 2003
32×7×41 Posts |
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#3 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
198110 Posts |
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This thread reminds me of a very old Sci-Fi novel that I never read myself but was told about by a friend:
Person A: They have spaceships that can travel to the Moon. Person B: That's impossible. The power required for such a trip is enormous. Person A: Yes, but they are using steam-engines to power their ships. ![]() Last fiddled with by a1call on 2019-06-23 at 23:27 |
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#4 | |
If I May
"Chris Halsall"
Sep 2002
Barbados
2×3×1,567 Posts |
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I fail to understand why SETI listens for low-band microwaves when higher frequency photons are more likely to be used for long distant communications. Maybe I'm just stupid. A non-zero probably. |
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#5 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
7·283 Posts |
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At the risk of further off tracking, I agree that SETI is based on assuming the ET to have mastered capabilities that we did not possess a mere 200 years ago such as radio communication as well as Amplitude-Modulation which is only one of the many different possibilities of using electromagnetic waves, Yes there are more probable means than used by SETI. But that's a Can-of-Worms best left unopened in a Wikipedia-Obsessed, Democratically-Dictated-Science, audience.
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#6 |
Sep 2002
Database er0rr
22·883 Posts |
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One more datum:
Code:
[87075848191, 21] |
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#7 |
Sep 2002
Database er0rr
22·883 Posts |
![]() Code:
? p=58133053441;for(k=1,1000000000,if(Mod(2,2*k*p+1)^p==1,print(k))) ? ## *** last result computed in 25min, 51,820 ms. |
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#8 |
"Robert Gerbicz"
Oct 2005
Hungary
1,429 Posts |
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#9 | |
Apr 2019
5·41 Posts |
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already and no factors. Your code above is up to ~66.6bits Code:
? log(2*1000000000*58133053441+1)/log(2) %1 = 66.655992491035654326600824278847640961 Last fiddled with by hansl on 2019-06-24 at 07:09 |
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#10 |
Sep 2002
Database er0rr
22·883 Posts |
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I am testing 76 to 77 bits
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#11 |
Apr 2019
20510 Posts |
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OK, i'm ~70% done with 75-76. And I've started 77-78 and 78-79 on other boxes.
BTW, I can't wait to upgrade one of my workstations. I recently ordered parts to take it from 6C/12T up to (dual socket) 24C/48T ... 4x the cores ![]() edit: No Factor from 75-76 bits. Last fiddled with by hansl on 2019-06-24 at 07:46 |
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