20201208, 10:16  #1 
Aug 2020
2^{4} Posts 
Primality Test Formula
Primality Test Formula
We can determinate if one number is prime with the modulo operation. https://www.researchgate.net/publica...y_Test_Formula 
20201208, 18:56  #2  
Dec 2017
2^{4}·3·5 Posts 
Quote:
I don't understand this part of the paper and to what number do I raise it to for the order of the derivative is it a random number? Quote:
(2 (2 + 3 x^(2/(2*m))))/(3 x^((n)/(2*m)) Last fiddled with by ONeil on 20201208 at 19:00 

20201208, 22:04  #3 
"TF79LL86GIMPS96gpu17"
Mar 2017
US midwest
47×151 Posts 
Seems like the long way around the barn, given that the pdf states finding it prime in 30 seconds while https://www.alpertron.com.ar/ECM.HTM does it in under 1 second including internet delays.

20201209, 02:28  #4 
Romulan Interpreter
"name field"
Jun 2011
Thailand
2×47×109 Posts 
Just a big pile of bullshit, from the beginning to the end. "If some number mod an even number is even, then you have to read another paper of mine, to see how to test if that's prime". Breaking news, an odd can't be even mod even. If that happens, your number is even and you don't need any formula. Your conclusion at the end of the document: "Conclusion: I lost 30 seconds of my life testing if that number was prime". My conclusion after reading it: "I want them back".
Last fiddled with by LaurV on 20201209 at 02:31 
20201209, 08:57  #5 
Aug 2020
2^{4} Posts 
The bound (the number in green) raise with the order of the derivative. For example if you want to test 10001 and the 40th derivative gives you a bound of 9001 you need to increase the order of the derivative.

20201209, 08:58  #6 
Aug 2020
10_{16} Posts 
I also tried to solve for x but I didn´t found anything interesting

20201209, 09:01  #7 
Aug 2020
10000_{2} Posts 
Primality Test Formula
I understand now your question.
I dont study deeply the relation between the bound and the order of the derivative. So take like a rndom number that you must increase to a number bigger than the number to test 
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