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Old 2019-08-24, 01:06   #485
ixfd64
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Quote:
Originally Posted by Madpoo View Post
I don't know who that user is, but if I ever meet him/her, I'll buy 'em a drink of their choice.
Someone said his forum name was "error." However, he has neither confirmed nor denied this.
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Old 2019-08-24, 01:33   #486
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Quote:
Originally Posted by Madpoo View Post
I don't know who that user is, but if I ever meet him/her, I'll buy 'em a drink of their choice.
How many GHz days must one accumulate in order for you to buy them a nice glass of Macallan 25?
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Old 2019-08-24, 14:15   #487
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Quote:
Originally Posted by mathwiz View Post
How many GHz days must one accumulate in order for you to buy them a nice glass of Macallan 25?
Apparently not more than 663000/year. See #17 at https://www.mersenne.org/report_top_500/
But madpoo did not state his requirements, which could be identifying and implementing and running a novel approach at scale.

Last fiddled with by kriesel on 2019-08-24 at 14:17
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Old 2019-08-24, 20:15   #488
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As an alternative for getting a free drink, I have no doubt that Madpoo as well as many others (some might insist for the drink to be nonalcoholic) will be glad to pay for a drink if you can find a factor for M1277.
Even, TJAOI hasn't given a factor for that yet, AFAIK.

Last fiddled with by a1call on 2019-08-24 at 20:16
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Old 2019-08-24, 22:31   #489
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Quote:
Originally Posted by a1call View Post
Even, TJAOI hasn't given a factor for that yet, AFAIK.
Not even Ryan Propper...
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Old 2019-08-25, 05:32   #490
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Quote:
Originally Posted by kriesel View Post
Apparently not more than 663000/year. See #17 at https://www.mersenne.org/report_top_500/
But madpoo did not state his requirements, which could be identifying and implementing and running a novel approach at scale.
I also didn't specify drink size... hmm... I hadn't thought through some of the pricier drinks out there, but my "out" is that by "drink" I could be referring to as little as a teaspoon-full.

Would they serve such a tiny amount?
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Old 2019-08-31, 10:31   #491
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Quote:
Originally Posted by a1call View Post
As an alternative for getting a free drink, I have no doubt that Madpoo as well as many others (some might insist for the drink to be nonalcoholic) will be glad to pay for a drink if you can find a factor for M1277.
I will buy a drink for whoever gets a factor of M1279. You won't argue for plus or minus two, would you?
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Old 2019-08-31, 10:47   #492
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Quote:
Originally Posted by LaurV View Post
I will buy a drink for whoever gets a factor of M1279.
M1279 = (2^1279-1) * 1

There you go, both factors.

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Old 2019-08-31, 12:55   #493
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Giving a factor for M1277 is easy as long as you don't ask for the decimal expansion

<br />
GCD\left( \left( \sqrt {M1277}\backslash 1\right) !,M1277\right)<br />
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Old 2019-09-01, 12:51   #494
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Quote:
Originally Posted by a1call View Post
Giving a factor for M1277 is easy as long as you don't ask for the decimal expansion

GCD\left( \left( \sqrt {M1277}\backslash 1\right) !,M1277\right)
I think that if all prime factors of M1277 are less than its square root, the GCD will give you M1277.
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Old 2019-09-01, 13:58   #495
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Quote:
Originally Posted by alpertron View Post
I think that if all prime factors of M1277 are less than its square root, the GCD will give you M1277.
Looks like I was too quick at going and having a glass of orange juice.

Since it seems impossible to parse # in LaTeX how about:

GCD((sqrt(M1277)\1)#,M1277)


Would that fair any better?
Now only one of the factors can be in common if any are powers.
And since M1277 is not a primorial something must be uncommon.

ETA I realize that I was wrong and the primorial does not fair any better. Thanks for pointing that out.

Last fiddled with by a1call on 2019-09-01 at 14:23
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