20090719, 23:25  #12 
Apr 2009
near Chicago
2·11 Posts 

20090719, 23:30  #13 
"Kyle"
Feb 2005
Somewhere near M50..sshh!
1101111110_{2} Posts 
It makes sense if you acknowledge K to be an integer, and n to be an integer, then 2^n is always an integer, multiplied by another integer (k) will always be an integer.
Last fiddled with by Primeinator on 20090719 at 23:30 
Thread Tools  
Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Riesel base 3 reservations/statuses/primes  KEP  Conjectures 'R Us  1040  20200713 07:31 
Riesel Primes k*2^n1, k<300 [Part II]  Kosmaj  Riesel Prime Search  991  20200622 09:27 
Proth and Riesel Primes  lukerichards  Number Theory Discussion Group  7  20180120 16:47 
Sierpinski/Riesel Base 5: Post Primes Here  robert44444uk  Sierpinski/Riesel Base 5  358  20081208 16:28 
Riesel.15k.org LLRnet Primes Found!  SlashDude  15k Search  3  20040614 16:07 