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2017-12-30, 06:37   #155
retina
Undefined

"The unspeakable one"
Jun 2006
My evil lair

10101010011112 Posts

Quote:
 Originally Posted by DanielBamberger How long is the longest string of 1's?
If there is only one of something can it be considered the longest? Compared to what?

So much impatience in this thread. Don't ya'all have something else more important to worry about?

 2017-12-30, 07:04 #156 Mark Rose     "/X\(‘-‘)/X\" Jan 2013 Ͳօɾօղէօ 2×7×199 Posts So if you wanted to print the full decimal expansion on US letter sheets at 6 point size with ½" margins, it would take approximately 2500 pages.
2017-12-30, 07:19   #157
DanielBamberger

"Daniel Bamberger"
Nov 2017
Marburg, Germany

2710 Posts

Quote:
 Originally Posted by Mark Rose So if you wanted to print the full decimal expansion on US letter sheets at 6 point size with ½" margins, it would take approximately 2500 pages.

2017-12-30, 08:33   #158
Mark Rose

"/X\(‘-‘)/X\"
Jan 2013
Ͳօɾօղէօ

278610 Posts

Quote:
I guess if I double-sided it, it would take only 1250 pages. I forgot you could do that with paper haha

2017-12-30, 10:54   #159
0PolarBearsHere

Oct 2015

2·7·19 Posts

Quote:
 Originally Posted by chalsall Is that anything like "What is the sound of one hand clapping?"

Quote:
Now they can make a sequel.

Last fiddled with by 0PolarBearsHere on 2017-12-30 at 10:55

 2017-12-30, 18:34 #160 daxmick     Feb 2014 10101002 Posts Yay! 2017 didn't get passed by without a Mersenne Prime being found. It was a close one though! We need to get more compute!
 2017-12-30, 19:23 #161 ATH Einyen     Dec 2003 Denmark 2×3×11×43 Posts CUDALucas run is finished at 4320K: M( 7xxxxxxx )P, n = 4320K, CUDALucas v2.05.1 That "P" is the very subtle sign saying "Prime!". Also another Prime95 run using 29.4 build 5 at 4096K. The original and Madpoo's run was both using Prime95 28.9: M7xxxxxxx is prime! Wg4: F9C5D09F,00000000 The Penultimate LL step is a + this time, so we are at 25+ and 24-. (There are only 49 as M1 = 2^2-1 = 3 does not have a penultimate step)..
 2017-12-30, 19:54 #162 lycorn     Sep 2002 Oeiras, Portugal 25438 Posts Well, well, looks like we´ve done it again, didn´t we? What a nice way of wrapping 2017 up! It will be 16 years next month since I joined the project, and it´s good to see that our little community is still alive and kicking. Congrats everyone! (and no, I will not disclose the good news before the official announcement...)
2017-12-30, 20:31   #163
vasyannyasha

"Vasiliy"
Apr 2017
Ukraine

22×3×5 Posts

Quote:
 Originally Posted by Mark Rose So if you wanted to print the full decimal expansion on US letter sheets at 6 point size with ½" margins, it would take approximately 2500 pages.
I calculated that this number have approx 23.1 million digits,so this number close to M77000000.

2017-12-30, 20:52   #164
GP2

Sep 2003

50228 Posts

Quote:
 Originally Posted by ATH The Penultimate LL step is a + this time, so we are at 25+ and 24-. (There are only 49 as M1 = 2^2-1 = 3 does not have a penultimate step)..
More importantly, is the new exponent "Team 1" or "Team 3" ?

Code:
       2, 2
3, 3
5, 1
7, 3
13, 1
17, 1
19, 3
31, 3
61, 1
89, 1
107, 3
127, 3
521, 1
607, 3
1279, 3
2203, 3
2281, 1
3217, 1
4253, 1
4423, 3
9689, 1
9941, 1
11213, 1
19937, 1
21701, 1
23209, 1
44497, 1
86243, 3
110503, 3
132049, 1
216091, 3
756839, 3
859433, 1
1257787, 3
1398269, 1
2976221, 1
3021377, 1
6972593, 1
13466917, 1
20996011, 3
24036583, 3
25964951, 3
30402457, 1
32582657, 1
37156667, 3
42643801, 1
43112609, 1
57885161, 1
74207281, 1
So far the counts are:

Code:
mod 4
29  1
1  2
19  3
The Wagstaff conjecture says that 1 is actually more common than 3, although this effect is more pronounced at lower exponent ranges.

On a related note, if it's 1 or 7 mod 8, then the search for primitive trinomials can begin again.

The counts for that are:

Code:
       2, 2
3, 3
5, 5
7, 7
13, 5
17, 1
19, 3
31, 7
61, 5
89, 1
107, 3
127, 7
521, 1
607, 7
1279, 7
2203, 3
2281, 1
3217, 1
4253, 5
4423, 7
9689, 1
9941, 5
11213, 5
19937, 1
21701, 5
23209, 1
44497, 1
86243, 3
110503, 7
132049, 1
216091, 3
756839, 7
859433, 1
1257787, 3
1398269, 5
2976221, 5
3021377, 1
6972593, 1
13466917, 5
20996011, 3
24036583, 7
25964951, 7
30402457, 1
32582657, 1
37156667, 3
42643801, 1
43112609, 1
57885161, 1
74207281, 1
Code:
mod 8
19  1
1  2
9  3
10  5
10  7

2017-12-30, 21:24   #165
Batalov

"Serge"
Mar 2008
Phi(3,3^1118781+1)/3

23×1,129 Posts

Quote:
 Originally Posted by ATH ... The Penultimate LL step is a + this time, so we are at 25+ and 24-. (There are only 49 as M1 = 2^2-1 = 3 does not have a penultimate step)..
I suppose you will get the s0 = 10 value as well, no doubt.
As for s0 = 2/3, I am curious to learn if the Penultimate LL value is proven to be a simple function of p ...or only conjectured? Anyone?

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