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Old 2017-12-30, 06:37   #155
retina
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Quote:
Originally Posted by DanielBamberger View Post
How long is the longest string of 1's?
If there is only one of something can it be considered the longest? Compared to what?

So much impatience in this thread. Don't ya'all have something else more important to worry about?
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Old 2017-12-30, 07:04   #156
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So if you wanted to print the full decimal expansion on US letter sheets at 6 point size with ½" margins, it would take approximately 2500 pages.
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Old 2017-12-30, 07:19   #157
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Quote:
Originally Posted by Mark Rose View Post
So if you wanted to print the full decimal expansion on US letter sheets at 6 point size with ½" margins, it would take approximately 2500 pages.
Sounds about right. https://www.youtube.com/watch?v=tlpYjrbujG0
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Old 2017-12-30, 08:33   #158
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Quote:
Originally Posted by DanielBamberger View Post
I guess if I double-sided it, it would take only 1250 pages. I forgot you could do that with paper haha
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Old 2017-12-30, 10:54   #159
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Quote:
Originally Posted by chalsall View Post
Is that anything like "What is the sound of one hand clapping?"
https://www.youtube.com/watch?v=RUzbmIKVAHo

Quote:
Originally Posted by DanielBamberger View Post
Now they can make a sequel.

Last fiddled with by 0PolarBearsHere on 2017-12-30 at 10:55
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Old 2017-12-30, 18:34   #160
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Yay! 2017 didn't get passed by without a Mersenne Prime being found.

It was a close one though! We need to get more compute!
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Old 2017-12-30, 19:23   #161
ATH
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CUDALucas run is finished at 4320K:

M( 7xxxxxxx )P, n = 4320K, CUDALucas v2.05.1

That "P" is the very subtle sign saying "Prime!".


Also another Prime95 run using 29.4 build 5 at 4096K. The original and Madpoo's run was both using Prime95 28.9:

M7xxxxxxx is prime! Wg4: F9C5D09F,00000000

The Penultimate LL step is a + this time, so we are at 25+ and 24-.
(There are only 49 as M1 = 2^2-1 = 3 does not have a penultimate step)..
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Old 2017-12-30, 19:54   #162
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Well, well, looks like we´ve done it again, didn´t we?
What a nice way of wrapping 2017 up!

It will be 16 years next month since I joined the project, and it´s good to see that our little community is still alive and kicking.
Congrats everyone! (and no, I will not disclose the good news before the official announcement...)
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Old 2017-12-30, 20:31   #163
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Quote:
Originally Posted by Mark Rose View Post
So if you wanted to print the full decimal expansion on US letter sheets at 6 point size with ½" margins, it would take approximately 2500 pages.
I calculated that this number have approx 23.1 million digits,so this number close to M77000000.
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Old 2017-12-30, 20:52   #164
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Quote:
Originally Posted by ATH View Post
The Penultimate LL step is a + this time, so we are at 25+ and 24-.
(There are only 49 as M1 = 2^2-1 = 3 does not have a penultimate step)..
More importantly, is the new exponent "Team 1" or "Team 3" ?

Code:
       2, 2
       3, 3
       5, 1
       7, 3
      13, 1
      17, 1
      19, 3
      31, 3
      61, 1
      89, 1
     107, 3
     127, 3
     521, 1
     607, 3
    1279, 3
    2203, 3
    2281, 1
    3217, 1
    4253, 1
    4423, 3
    9689, 1
    9941, 1
   11213, 1
   19937, 1
   21701, 1
   23209, 1
   44497, 1
   86243, 3
  110503, 3
  132049, 1
  216091, 3
  756839, 3
  859433, 1
 1257787, 3
 1398269, 1
 2976221, 1
 3021377, 1
 6972593, 1
13466917, 1
20996011, 3
24036583, 3
25964951, 3
30402457, 1
32582657, 1
37156667, 3
42643801, 1
43112609, 1
57885161, 1
74207281, 1
So far the counts are:

Code:
mod 4
     29  1
      1  2
     19  3
The Wagstaff conjecture says that 1 is actually more common than 3, although this effect is more pronounced at lower exponent ranges.


On a related note, if it's 1 or 7 mod 8, then the search for primitive trinomials can begin again.

The counts for that are:

Code:
       2, 2
       3, 3
       5, 5
       7, 7
      13, 5
      17, 1
      19, 3
      31, 7
      61, 5
      89, 1
     107, 3
     127, 7
     521, 1
     607, 7
    1279, 7
    2203, 3
    2281, 1
    3217, 1
    4253, 5
    4423, 7
    9689, 1
    9941, 5
   11213, 5
   19937, 1
   21701, 5
   23209, 1
   44497, 1
   86243, 3
  110503, 7
  132049, 1
  216091, 3
  756839, 7
  859433, 1
 1257787, 3
 1398269, 5
 2976221, 5
 3021377, 1
 6972593, 1
13466917, 5
20996011, 3
24036583, 7
25964951, 7
30402457, 1
32582657, 1
37156667, 3
42643801, 1
43112609, 1
57885161, 1
74207281, 1
Code:
mod 8
     19  1
      1  2
      9  3
     10  5
     10  7
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Old 2017-12-30, 21:24   #165
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Quote:
Originally Posted by ATH View Post
...
The Penultimate LL step is a + this time, so we are at 25+ and 24-.
(There are only 49 as M1 = 2^2-1 = 3 does not have a penultimate step)..
I suppose you will get the s0 = 10 value as well, no doubt.
As for s0 = 2/3, I am curious to learn if the Penultimate LL value is proven to be a simple function of p ...or only conjectured? Anyone?
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