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#1 | ||
"Rashid Naimi"
Oct 2015
Remote to Here/There
197910 Posts |
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That does not sound right to me. Shouldn't that be something like: Quote:
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#2 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
1,979 Posts |
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Follow up question:
* Is there a (known) way to formulate N as a function of k? Thanks in advance. |
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#3 | |
"Robert Gerbicz"
Oct 2005
Hungary
26248 Posts |
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You can say stronger statement (following and modifying the proof) : there is c0>0 for that there is at least c0*n/log(n) primes in [n,2n]. Using this there is c1>0 for that for N=c1*n*log(n) there is at least n primes in [N,2N]. |
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#4 |
"Rashid Naimi"
Oct 2015
Remote to Here/There
1,979 Posts |
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Thank you very much for the confirmation and the formulation R. Gerbicz.
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