20201123, 23:04  #683 
"Ed Hall"
Dec 2009
Adirondack Mtns
3,539 Posts 
I reran the above using only 2^{4} and came up with 70 unbroken and 296 broken. This shouldn't be too far off. Some variations may not be considered, but the runs still appear to break much more often than not.
Perhaps I should look at other drivers/guides? I can't seem to find the page which describes the difference between drivers and guides. Is it still available somewhere? 
20201123, 23:34  #684 
"Curtis"
Feb 2005
Riverside, CA
1000111111111_{2} Posts 
Squaring the 31 is the manner in which one breaks 2^4 * 31.
Other powers of 2 would not be a driver; only the perfect number 496 = 2^4 * 31 is a driver. I believe the same is true for the other perfect numbers: Square the 3 or 7 or 127 to escape. 
20201124, 05:02  #685 
Romulan Interpreter
Jun 2011
Thailand
3·11·277 Posts 

20201125, 04:49  #686  
"Rich"
Aug 2002
Benicia, California
29·41 Posts 
Quote:
Continuing with 439^44. 

20201129, 10:50  #687 
Oct 2011
101111100_{2} Posts 
Page updated.
Many thanks to all for your help ! 
20201206, 15:03  #688 
May 2009
Russia, Moscow
4740_{8} Posts 
I'm done with base 79  all sequences in the table are >120 digits with >110 ECMed composites. Also I did some work with odd k's above the limit, will post results later.

20201206, 15:50  #689  
Oct 2011
2^{2}×5×19 Posts 
Quote:
Quote:
Many thanks ! 

20201213, 12:13  #690 
Sep 2008
Kansas
41×79 Posts 
One of the next logical tables would be 242 (2 * 11^2). I've taken it to i=52.
Edit: Updates to tables 29, 220, 284. Last fiddled with by RichD on 20201213 at 12:16 
20201213, 15:02  #691  
Oct 2011
2^{2}×5×19 Posts 
Quote:
I will update all the bases on the weekend of December 20th. And I will also add the base 242 that you calculated. Thus, the base 200 = 2 * 10^2 will be missing, if you like the bases for which the calculations end for all the exponents. These bases will be interesting for future analyses. 

20201213, 17:43  #692 
Sep 2008
Kansas
41·79 Posts 

20201213, 17:52  #693 
Oct 2011
2^{2}·5·19 Posts 
OK, many thanks for your help !

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