A new factor of F11?!

siegert81 · 2018-01-23, 11:36

When using Leonid Durman's "Fermat.exe version 4.4, beta" software, I got the following result:

Quote:

found m=10, k=395937, n=14
395937.2^14+1 divides F_10

found m=12, k=11613415, n=14
11613415.2^14+1 divides F_12

found m=11, k=19009615, n=14
19009615.2^14+1 divides F_11

I used the input "n = 14 to 14" and "k = 9 to 100000000"

The first two factors are known, but the third factor is not listed on Wilfrid Keller's list. I'm assuming that it's not a new factor and that this "Fermat.exe" program is somehow flawed.

kar_bon · 2018-01-23, 12:44

It's the product of the two small factors found already.

siegert81 · 2018-01-24, 04:35

Ah.

Well, that solves that mystery...

Thanks!

2018-01-23, 12:44	#2
kar_bon Mar 2006 Germany 2,879 Posts	It's the product of the two small factors found already. Last fiddled with by kar_bon on 2018-01-23 at 12:45

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2018-01-24, 04:35	#3
siegert81 Dec 2010 2·37 Posts	Ah. Well, that solves that mystery... Thanks!