Another "how to prove"

George M · 2018-01-02, 07:20

Quote:

Originally Posted by George M

$p_{n + 1} \ = \ \{\sum_{k = 1}^{n}(p_{k + 1} \ - \ p_{k}) \ : \ p_m \ = \ m^{th} \ prime \ number\}$

The equation is incorrect, but seemingly correct if you add 2 to the RHS. Can anybody demonstrate a proof?

danaj · 2018-01-02, 18:02

Moved from a a post on a Prime Gap Searches thread.

science_man_88 · 2018-01-02, 18:08

Quote:

Originally Posted by George M

The equation is incorrect, but seemingly correct if you add 2 to the RHS. Can anybody demonstrate a proof?

You are summing the prime gaps, you need to add 2 because 2 is tje first prime.

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2018-01-02, 18:02	#2
danaj "Dana Jacobsen" Feb 2011 Bangkok, TH 2²·227 Posts	Moved from a a post on a Prime Gap Searches thread.