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 2010-04-01, 10:18 #1 Merfighters     Mar 2010 On front of my laptop 7·17 Posts My new discovery!! Decrypt that RSA encrypted sentence to find out! Encrypted sentence: 516706041301498569139808807078772714750649530964326734 N: 653465099972074208154022739130081051703785966122945327 E: 6725175846738058345386447704209495270349 10~35: A~Z 36: , 37: . 38: ? 39~48: 0~9 49: ! 99: (space)
 2010-04-01, 10:50 #2 Merfighters     Mar 2010 On front of my laptop 7·17 Posts Whoops! Someone please move this thread to Lounge?
 2010-04-01, 11:02 #3 Raman Noodles     "Mr. Tuch" Dec 2007 Chennai, India 23518 Posts This is a good puzzle 102527182199152424214949 APRIL FOOL!! N = p.q p = 751567152453117379356088079 q = 869470010549506074668255713 phi = (p-1)(q-1) D = E-1 (mod phi) such that E.D = 1 (mod phi) x = yD (mod N) y = xE (mod N) where x is the plain text y is the cipher text Good work man!! Where did you get up those all of your keys from, in order to generate that up only, thus?
2010-04-07, 11:46   #4
Merfighters

Mar 2010
On front of my laptop

7×17 Posts

Quote:
 Originally Posted by Raman Good work man!! Where did you get up those all of your keys from, in order to generate that up only, thus?
1. I used my own program to generate numbers.
2. I entered it to Dario Alpern's ECM applet to find a prime.
3. And I used Dario Alpern's another applet to do the rest.

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