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#12 |
Romulan Interpreter
Jun 2011
Thailand
3×55 Posts |
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Not really, you may have long words (unambiguous) whose non-terminal letters are not part of any other word, this is not forbidden in any kind of crosswords. For example, you have a 6 letters horizontal word starting in R1C1, then R2C4 can be black, if the letter in R1C4 is not ambiguous. Your requirement is very restrictive, it would restrict a lot the places where the black dots can go, for example, you would not have any black dot in row 2, nor any in column 2, nor any in row N-1, not any in column n-1, etc. (you can go on from here), because any such dot will insulate a letter in either row1, or col1, etc.
Last fiddled with by LaurV on 2021-02-12 at 04:20 Reason: clarify |
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#13 | |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
29×211 Posts |
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Therefore: 3600 - 450 = 3150 ![]() I hope we don't keep seeing more and more ever restrictive rules being added at random intervals. ![]() |
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#14 | |
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
3·3,163 Posts |
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#15 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
29×211 Posts |
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#16 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
137478 Posts |
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You can have black spaces in any column or row. I didn't see any rule saying there can't be two together.
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#17 | |
Jan 2020
31 Posts |
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I slightly modifìed my candidate to fit your additional constraint. Less words, but more symmetries. 86 words: 000100010001000 000100010001000 000000010000000 110001111100011 000000010000000 000100010001000 000100000001000 111111000111111 000100000001000 000100010001000 000000010000000 110001111100011 000000010000000 000100010001000 000100010001000 every letter belongs to at least one 3x3 square |
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#18 | |
Romulan Interpreter
Jun 2011
Thailand
100100100111112 Posts |
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If you ask me what are "my" rules for a good crossword, then those should be only one: no ambiguity of the solution. This means that once you show me the solution, I would open my mouth large and make big eyes of awe and say "yes!". I wouldn't care about walls, corners, and stuff. But the crosswords I used to solve a hundred years ago, when the crosswords were "something", i.e. before a lot of easy crap flooded the markets, had very well defined rules, like "no closed corners" (which means you could not have black squares in, say, R1C4 and R2C3, because in this case the R1C3 is a "closed" cell, and upper-left corner becomes a "closed corner", you would have a lot of possibilities to fill it, especially if you speak a "flexed" language, as Romanian; however, closed cells are accepted if not a lot, and not ambiguous by definition), or "no walls" (i.e. no two black squares can share an edge), etc. But what Bobby asked, every letter be part of two words, that would be a VERY restrictive condition, which I didn't see in almost any rebus I solved, except accidentally (in very good, awarded, rebuses). (P.S. In Romanian, rebus is just an advanced form of crossword - Ro="cuvinte încrucișate" - and in many contexts, they mean the same stuff and are interchangeable, but I just realized now, looking on wikipedia, that, in English, rebus is a different kind of logic game, so forgive me if I use the term to mean "crosswords"). So, what is shown on wikipedia as "american" or "australian/british", or "japanese" -style grids, would all be forbidden in competitions I used to participate in my youth (they all have closed corners, walls, and ambiguities), and they won't be published in "good" magazines. Also, the symmetry was not a requirement, but it was highly appreciated by solvers. Example: (random from web, Romanian Rebus Magazine, sometime in the '80s): Please note that Bobby's rules will forbid all 3 grids in the example, as they all have at least 4 letters which are part of a single word. Last fiddled with by LaurV on 2021-02-13 at 06:24 |
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#19 |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
29×211 Posts |
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#20 |
Romulan Interpreter
Jun 2011
Thailand
3×55 Posts |
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#21 | |
Undefined
"The unspeakable one"
Jun 2006
My evil lair
17E716 Posts |
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Nope, I don't see it?
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#22 |
Romulan Interpreter
Jun 2011
Thailand
3×55 Posts |
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Which part of "if" (your condition applies) and "would" don't you get?
I thought you are native speaker. If "any letter must be a part of 2 words", then there would be no dark square allowed in the second ring. Or... oh? do you mean that you can have black square in the second ring, in case the correspondent "singled" square in the first ring is also black? Like a R2C2 black square will force all R1C1, R1C2 and R2C1 to be black? Grrr, yeah, this way you can, but I somehow interdicted "walls" in my concept... ![]() |
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