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#1 |
Jun 2003
157910 Posts |
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Consider a prime p and a natural number n<p then K*p+n is composite atleast twice with k in the range 0<=k<=(p-1)
I think the above holds for all primes, I have a simple proof for this. Lets see if you can find it. Citrix |
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#2 | |
Jun 2003
1,579 Posts |
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Sorry Citrix |
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