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#1 |
Feb 2021
38 Posts |
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2^p - 1, where p is prime number is always prime number, for example:
2^7 - 1 is 127, 2^127 - 1 is 170141183460469231731687303715884105727, 2^170141183460469231731687303715884105727 - 1 is big number, but its prime number, so it's eveidnce that there is infinity mersenne prime numbers |
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#2 |
Sep 2002
Database er0rr
2×1,811 Posts |
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https://primes.utm.edu/mersenne/index.html#unknown
Proving a ~10^51217599719369681875006054625051616349 digit number prime is beyond all known technolgy. Last fiddled with by paulunderwood on 2021-02-22 at 01:54 |
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#3 |
"Serge"
Mar 2008
Phi(4,2^7658614+1)/2
9,391 Posts |
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#4 |
6809 > 6502
"""""""""""""""""""
Aug 2003
101×103 Posts
11·863 Posts |
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#5 |
"Composite as Heck"
Oct 2017
79010 Posts |
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Unfortunately you forgot to end with QED so the proof is inadmissible.
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#6 |
Feb 2021
3 Posts |
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#7 |
Sep 2002
Database er0rr
E2616 Posts |
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#8 |
Feb 2021
3 Posts |
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#9 |
"Viliam Furík"
Jul 2018
Martin, Slovakia
2×223 Posts |
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#10 |
Feb 2017
Nowhere
17×263 Posts |
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MODERATOR NOTE: Thread closed.
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#11 | ||
Undefined
"The unspeakable one"
Jun 2006
My evil lair
137548 Posts |
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Quote:
How back to you go? Because 5 is not a Mersenne prime. And your example above, 2 is not a Mersenne prime either, so the sequence 2, 3, 7, 127, ... doesn't start with a Mersenne prime. And if you conveniently ignore the first term then 3, 7, 127, ... does match your claim, but then 31, 2147483647, ... fails your claim. You can't have it both ways. ![]() |
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