20100902, 13:37  #12 
Aug 2002
Buenos Aires, Argentina
31×43 Posts 

20100903, 10:20  #13 
(loop (#_fork))
Feb 2006
Cambridge, England
2·29·109 Posts 
115^128+1 completed (250 curves at 1e7 were enough); result in factordb.com
101^128+1 also completed So: 400 curves at 1e7 on the notpreviouslyfullyfactored numbers in {94..115}^128+1. This took one night on 16 threads on a macpro. 35^128+1 currently finishing linalg Last fiddled with by fivemack on 20100904 at 07:50 
20100903, 21:15  #14 
(loop (#_fork))
Feb 2006
Cambridge, England
2·29·109 Posts 
35^128+1 = 2 * 769 * 77310721 * 465774259823008864434412748488285224928909076514051885029488061896961 * P118

20100903, 21:25  #15 
Banned
"Luigi"
Aug 2002
Team Italia
2^{5}×149 Posts 

20100903, 21:48  #16 
A Sunny Moo
Aug 2007
USA (GMT5)
79^{2} Posts 

20100904, 04:24  #17 
Oct 2004
Austria
7×353 Posts 

20100904, 07:49  #18 
(loop (#_fork))
Feb 2006
Cambridge, England
2·29·109 Posts 
yes; x^5+35^2, x=35^26; alim=rlim=15M, Q=7.5M17.5M, 28bit large primes. 494 CPUhours sieving on 8x K10+3x core2, 48 CPUhours on 4xphenom to do the matrix step. A trivial exercise.

20100904, 08:21  #19 
Banned
"Luigi"
Aug 2002
Team Italia
4768_{10} Posts 

20100913, 05:36  #20 
Mar 2003
New Zealand
13·89 Posts 
I found this p44 factor after about 500 curves with B1=11e6: 14571454116637488440882751359138387691414529  8^(2^8) + 5^(2^8)
If anyone wanted to finish some of these off with GNFS, I think the two smallest remaining composites (with bases <= 12) are now: 11^(2^8) + 3^(2^8) = 2 . 3430486387626057217 . 1826300595737909153428993580626433 . 132980092956629419115138154564331009 . 11765487608073254883107740674172674049 . C143 8^(2^8) + 5^(2^8) = 206102775026177 . 25083346678208656976952833 . 14571454116637488440882751359138387691414529 . C149 
20100913, 05:46  #21  
"Robert Gerbicz"
Oct 2005
Hungary
1411_{10} Posts 
Quote:


20100913, 06:21  #22  
Mar 2003
New Zealand
2205_{8} Posts 
Quote:


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